Answer:
Explanation:
Within a duration of 60 seconds, six waves are observed.
With a total of 6 waves,
this equates to 3 wavelengths.
As a result,
the period for each wavelength is calculated as 60 divided by 3.
Thus, period = 20 seconds.
According to the frequency-period relationship,
f = 1 / T
f = 1 / 20
f = 0.05 Hz
Answer: a) t = 1.8 x 10^2 seconds; b) t = 54 seconds; c) t = 49 seconds. Explanation: a) To determine the time of a stationary passenger on the sidewalk, we use the position formula. Given the constant speed of the walkway, we can calculate the time taken for set distances accordingly. This calculation extends into cases where combined velocities for walking are involved in subsequent queries.
Response:

Clarification:
We need an expression that shows how much water has been drained from the tub. This is represented by v, which indicates how many gallons have flowed out since the plug was taken out. Each gallon removed equates to 8.345 pounds of water, so the weight of the drained water Q in pounds as a function of v can be expressed as:

Where v signifies the number of gallons emptied from the tub.
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Provided Information:
Length of inclined plane = 8 m
Height of inclined plane = 2 m
Weight of the ice block = 300 N
Required Information:
Force needed to push ice block = F =?
Answer:
Force needed to push the ice block = 75 N
Explanation:
The required force to push this ice block up an inclined plane is given by
F = Wsinθ
where W is the weight of the ice block and θ is the angle indicated in the attached image.
Using trigonometric ratios,
sinθ = opposite/hypotenuse
where the opposite side is the height of the inclined plane and the hypotenuse is the length of the inclined plane.
Thus, sinθ = 2/8
θ = sin⁻¹(2/8)
which leads to θ = 14.48°
Therefore, F = 300*sin(14.48)
results in F = 75 N
This indicates that a force of 75 N is necessary to push the ice block on the specified inclined plane.
The angle formed with the positive x-axis is 120 degrees. We can assume that this angle is determined in a counterclockwise direction from the positive x-axis. The x-component of the vector can be calculated as: x-component = 10 cos(120) = -5. The vector's y-component is determined as: y-component = 10 sin(120) = 8.66. The x-component equates to -5 while the y-component equals 8.66.