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Bingel
25 days ago
5

Harmony used discarded paper to make notepads for her friends. She would fold five letter size pieces of paper three times then

cut along the lines. She would then stack the smaller note papers and staple them together. How long would one notepad last if someone wrote ten notes per day? 1 piece of paper=1 note
Mathematics
2 answers:
zzz [11.8K]25 days ago
7 0
Initially, the first fold creates two smaller sheets of paper
. The second fold of these sheets results in 4 smaller pieces of paper
. A third fold of the resultant pieces leads to 8 smaller pieces of paper

. Therefore, when five letter-sized sheets are folded three times, they yield 8 x 5 = 40 notes

. Consequently, one notepad comprises 40 notes

. If an individual writes ten notes daily, a single notepad will last for 4 days
.
Svet_ta [12.2K]25 days ago
5 0
The duration is 4 days. Step-by-step explanation: Harmony repurposed discarded paper to create notepads for her friends. She folded five letter-sized sheets of paper three times and then made cuts along the folds. Afterward, she stacked the resulting smaller note sheets and stapled them together. Folding each paper three times results in 8 smaller sections per letter-sized sheet. Therefore, multiplying 8 sections by 5 papers gives 40 note sheets. Since individuals write 10 notes daily, it will last 4 days.
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A customer buys a different book that has an original selling price of $38. The book is discounted 25%. The customer must pay a
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20 days ago
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Consider the equation log(3x - 1) = log28. Explain why 3x - 1 is not equal to 8. Describe the steps you would take to solve the
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This is due to the distinct properties of logarithms in comparison to algebra. The expression log(3x - 1) is interpreted as log 3x divided by log 1. If we proceed with rearranging and solving for x, we arrive at: log(3x - 1) = log28, log 3x/log 1 = log 28, resulting in log 3x being equal to log 28 multiplied by log 1 which equals 0. Thus, 3x = 10⁰ = 1, leading to 3x = 1 and x = 1/3. Therefore, it follows that 3x - 1 equals 3(1/3) - 1 = 0.
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4 days ago
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Which statements are true regarding the diagram? Check all that apply.
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Answer:

2.CE lies on line m.

4.Ray AD is identical to ray AC.

6.Angle ECB is formed by CE and CB.

Step-by-step explanation:

A diagram has been provided.

Our task is to identify the valid statements regarding the diagram.

1.CB is found on line n.

CB does not align with line n since points C and B do not lie on that line.

Thus, this statement is false.

2.CE is situated on line m.

CE is indeed positioned on line m because points C and E are both on this line.

This statement is accurate.

3.Ray BC is equivalent to ray CB.

A ray begins at a single point and continues indefinitely without a terminal point.

Ray CB starts at point C and stretches out from point B.

However, ray BC does not exist.

This statement is therefore false.

4.Ray AD is equivalent to ray AC.

Both AD and AC are rays.

They are equivalent since both originate from point A and extend in the same direction.

5.Angle EAD is formed from AE and DA.

This is false because angle EAD is created by ray AE and ray AD, not by ray DA.

6.Angle ECB is generated by CE and CB.

This is true as angle ECB is made by ray EC and ray BC.

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A frog is sitting exactly in the middle of a board that is five feet long. Every ten seconds he jumps one foot to the left or on
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Answer:

Given that the frog jumps every 10 seconds

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  • It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
  • Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
  • Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.

Step-by-step explanation:

A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.

Every 10 seconds, the frog jumps left or right.

If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.

If it jumps as LLRLL, it will jump off the board after fifty seconds.

Given that the frog jumps every 10 seconds

   (using digits from a random number table)

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