A car tire has a pressure of 2.38 atm at 15.2 c. If the pressure inside reached 4.08 atm, the tire will explode. How hot would t

Answer:

Amount of salt in 1 L seawater = 34 g

Explanation:

Based on Archimedes' principle, the mass of fresh water and the mass of the cup are equal to the mass of the same volume of seawater.

The mass of freshwater can be calculated using density times volume.

1 cm³ is equivalent to 1 mL.

The mass of freshwater is 0.999 g/cm³ multiplied by 735 cm³, which results in 734.265 g.

The total mass of the freshwater and cup combined is 734.265 g plus 25 g, equating to 759.265 g.

This means the mass for an equal volume of seawater is 759.265 g.

The volume of the seawater displaced is 735 mL, which is 0.735 L (assuming the cup's volume can be disregarded).

We know that 1 liter equals 1000 cm³ or 1000 mL.

The density of seawater can be determined as mass divided by volume.

The density of seawater becomes 759.265 g divided by 0.735 L, yielding 1033.01 g/L.

Conversely, the density of freshwater in g/L is calculated as 0.999 g/(1/1000) L, equating to 999 g/L.

The mass of salt dissolved in 1 liter of seawater is calculated as 1033.01 g - 999 g, which equals 34.01 g.

Thus, the amount of salt in 1 L of seawater is 34 g.

Option d is the correct choice, as both belong to the alkali metals category (group one).

I hope this is useful......

The concentration of the HCl solution can be determined as follows:

The reaction equation is written as

NaOH + HCl = NaCl + H2O

Next, the moles of NaOH are calculated: moles = molarity x volume /1000

= 5 x 2/1000 = 0.01 moles

Using the mole ratio of NaOH to HCl, which is 1:1, the moles of HCl is also equal to 0.01 moles

The concentration is given by: concentration = moles/volume x 1000

= 0.01/10 x 1000 = 1M

Answer:

The temperature of a vessel at a pressure reading of 1.250 atm is 296.43 K.

Explanation:

At standard temperature and pressure (STP), the temperature is valued at 273.15 K with a pressure of 1.000 atm.

If the pressure is measured as 1.250 atm at temperature T.

Applying Gay Lussac's law:

(When volume is constant)

At a pressure of 1.250 atm, the temperature of the vessel is 296.43 K.