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28 days ago

Three glass bulbs, joined by closed stopcocks, have the following volumes and initial pressures of the specified gases.

Chemistry

1 answer:

castortr0y [2.7K]28 days ago

8 0

Answer:

P = 0.75 atm

Explanation:

According to Boyle's law

${P_A}\times {V_A}+{P_B}\times {V_B}+{P_C}\times {V_C}={P}\times {V}$

Given,

For Bulb A

Pressure = 190 torr

The conversion from P(torr) to P(atm) is as follows:

$P(torr)=\frac {1}{760}\times P(atm)$

Thus,

Pressure = 190 / 760 atm = 0.25 atm

Volume = 200 mL

For Bulb B

Pressure = 1 atm

Volume = 400 mL

For Bulb C

Volume = 1.00 L = 1000 mL

Pressure = 75.994 kPa

The conversion formula for pressure from KiloPascal to atm is written below:

P (kPa) = $\frac {1}{101.325}$ P (atm)

75.994 kPa = $\frac {75.994}{101.325}$ atm

So, Pressure = 0.75 atm

Furthermore, the total volume, V = 200 + 400 + 1000 mL = 1600 mL

Applying the above equation gives:

${0.25}\times {200}+{1.00}\times {400}+{0.75}\times {1000}={P}\times {1600}$

We find that the total pressure, P = 0.75 atm

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