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mr Goodwill
3 months ago
12

The loudness of a sound is inversely proportional to the square of your distance from the source of the sound. if your friend is

right next to the speakers at a loud concert and you are four times as far away from the speakers, how does the loudness of the music at your position compare to the loudness at your friend's position?
Physics
2 answers:
Yuliya22 [3.3K]3 months ago
5 0

Define loudness as L, distance as d, and k as the variation constant. The appropriate equation representing the relationship is:
                    L = k / d^2
For Situation 1,
                    L1 = k / d1^2
For Situation 2,
                    L2 = k / (d1 / 4)^2
To have equal k, it follows that L2 = 16 L1.
Thus, the loudness your friend experiences is 16 times greater than yours.

 
Sav [3.1K]3 months ago
3 0

Answer:

The loudness at your location amounts to just 1/16 of the loudness at your friend’s spot.

Explanation:

Loudness diminishes as the distance from the speaker increases

and it varies inversely with the square of the distance.

So, we have

L = \frac{k}{r^2}

Comparing loudness at two different distances gives

\frac{L_1}{L_2} = (\frac{r_2}{r_1})^2

Knowing that,

r_2 = 4 r_1

and thus

\frac{L_1}{L_2} = 4^2

L_2 = \frac{L_1}{16}

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A person shooting at a target from a distance of 450 metres finds that the sound of the bullet hitting the target comes 1 / 2 se
Sav [3153]

Answer:

1350 m/s

Clarification:

Bullet speed

The bullet travels 450 m

Sound travels a distance of 450 m

Using the equation S= V × t

==> t= S/V

Thus, the time for the bullet t1=450/vb

and the sound's travel time t2=450/vs

Given that there's a 1/2 sec interval from when the shot is fired to the moment the shooter hears the sound

==>  t1+t2= 1/2 sec

==> 450/vb+450/vs=0.5sec  ---- (1)

At a distance 'x' from both the gun and target, it takes 3 seconds for a person to hear the bullet sound from firing to impact.

Firing sound duration

n

Distance =x m

Speed of sound = V

time =T1

==> T1 = x/vs

During this time period, the bullet covers 450 m and the sound of impact travels a distance 'x'

The time taken for sound = 450/vb

The time it takes sound to travel distance 'x'= x/vs

therefore let T2= 450/vb + x/vs

However, all this occurs within 3 seconds, i.e., T = 3 sec

because firing takes place before hitting the target, implying the strike sound is heard in time T = T2-T1= 450/vb + x/vs -x/vs

Making T= 3sec

==> 3= 450/vb

==> vb= 1350 m/s

From equations 1 and 2

applying the same principle, in 3 seconds the observer sees the bullet travel 450 m and perceives the sound


3 0
2 months ago
A car covers 72 kilometers in the first hour of its journey. In the next hour, it covers 90 kilometers. What is the amount of wo
Softa [3030]
The work done can be calculated using the equation:

Work = Force x Distance = Change in kinetic energy

The kinetic energy is derived using the following formula: KE = (1/2)*m*v^2
Thus, the change in kinetic energy is calculated as (1/2)*m*(Vf)^2 - (1/2)*m*(Vo)^2

Where:

Vf represents the final speed = 90 kph = 25 m/s
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By substituting in the given values:

Work = (1/2)*2500*(25^2) - (1/2)*2500*(20^2) = 281250 J, which can also be represented as 2.8 x 10^5 Joules.

The correct choice among the options is A.
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The answer is 13900589.
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