Ask question

Ask question

All categories

1 month ago

12

The loudness of a sound is inversely proportional to the square of your distance from the source of the sound. if your friend is

right next to the speakers at a loud concert and you are four times as far away from the speakers, how does the loudness of the music at your position compare to the loudness at your friend's position?

2 answers:

Yuliya22 [3.3K]1 month ago

5 0

Define loudness as L, distance as d, and k as the variation constant. The appropriate equation representing the relationship is:
L = k / d^2
For Situation 1,
L1 = k / d1^2
For Situation 2,
L2 = k / (d1 / 4)^2
To have equal k, it follows that L2 = 16 L1.
Thus, the loudness your friend experiences is 16 times greater than yours.

Sav [3.1K]1 month ago

3 0

Answer:

The loudness at your location amounts to just 1/16 of the loudness at your friend’s spot.

Explanation:

Loudness diminishes as the distance from the speaker increases

and it varies inversely with the square of the distance.

So, we have

$L = \frac{k}{r^2}$

Comparing loudness at two different distances gives

$\frac{L_1}{L_2} = (\frac{r_2}{r_1})^2$

Knowing that,

$r_2 = 4 r_1$

and thus

$\frac{L_1}{L_2} = 4^2$

$L_2 = \frac{L_1}{16}$

You might be interested in

In a given city, the permissible limit of CO (carbon monoxide) in the air is 100 parts per million (ppm). The city monitors the

Sav [3153]

The city evaluates the continuous increase of carbon monoxide from different origins each year. According to calculations, in the year "C: 2019"<span> (rounded to the closest whole number), the concentration of CO will surpass the allowed threshold.

If this is not correct, feel free to inform me and I will find out the right answer. However, I am confident this is accurate.:) </span>

8 0

1 month ago

Read 2 more answers

A solid sphere is released from the top of a ramp that is at a height h1 = 2.30 m. It rolls down the ramp without slipping. The

Yuliya22 [3333]

Answer:

The horizontal distance d that the ball covers before it lands is 1.72 m.

Explanation:

Given,

Height of ramp $h_{1}=2.30\ m$

Height of bottom of ramp $h_{2}=1.69\ m$

Diameter = 0.17 m

We need to determine the horizontal distance d the ball travels before landing.

We need to calculate the time

Using the equation of motion

$h_{2}=ut+\dfrac{1}{2}gt^2$

$t=\sqrt{\dfrac{2h_{2}}{g}}$

$t=\sqrt{\dfrac{2\times1.69}{9.8}}$

$t=0.587\ sec$

Next, we can find the ball's velocity

Using the kinetic energy formula

$K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2$

$K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}\times(\dfrac{2}{5}mr^2)\times(\dfrac{v}{r})^2$

$K.E=\dfrac{7}{10}mv^2$

By applying the conservation of energy

$K.E=mg(h_{1}-h_{2})$

$\dfrac{7}{10}mv^2=mg(h_{1}-h_{2})$

$v^2=\dfrac{10}{7}\times g(h_{1}-h_{2})$

We substitute the values into the equation

$v=\sqrt{\dfrac{10\times9.8\times(2.30-1.69)}{7}}$

$v=2.922\ m/s$

Next, we determine the horizontal distance d the ball travels before landing

Using the distance formula

$d =vt$

Where. d = distance

t = time

v = velocity

We substitute the values into the formula

$d=2.922\times 0.587$

$d=1.72\ m$

Thus, the horizontal distance d that the ball travels before it lands is 1.72 m.

8 0

12 days ago

Two trains are headed towards each other on the same track unbeknownst to the engineers. One departs San Francisco. Its average

ValentinkaMS [3465]

Answer:

7.166 hours = 430 minutes.

Explanation:

As both trains are approaching each other on the same track, their relative speed is the sum of their individual speeds. Hence, the time until they intersect (and inevitably collide) is determined by how long it takes for speeds of 65 mph and 55 mph to cover the total distance of 860 miles. One train will cover part of the distance, while the other will cover the remainder. To calculate the required time, we can apply the formula:

1 hour ---> 120 miles

X ----> 860 miles; hence X = (860 miles * 1 hour)/120 miles = 43/6 hours = 7.16666 hours. To convert this into minutes, recall that 1 hour equals 60 minutes; therefore, 43/6 hours * 60 minutes/hour = 430 minutes.

7 0

1 month ago

A car with an initial velocity of 16.0 meters per second east slows uniformly to 6.0 meters per second east in 4.0 seconds. What

serg [3582]

(6-16)/4.0=-2.5 m/s²
The car's acceleration is -2.5 m/s²

5 0

1 month ago

The energy difference between the 5d and the 6s sublevels in gold accounts for its color. If this energy difference is about 2.7

Yuliya22 [3333]

The light's wavelength absorbed during the transition is 459 nm. Energy difference between the 5-d and the 6-s sub-levels in gold is expressed as ΔE. Let the wavelength associated with the electron's transition from the 5-d to the 6-s state be λ. The relationship that describes the connection between energy and wavelength is defined as: E = hc/λ, where E stands for photon energy, h represents Planck's constant, c is the speed of light, and λ denotes the wavelength of the photon. Therefore, the absorption wavelength in this transition stands at 459 nm.

8 0

1 month ago