A ten-loop coil having an area of 0.23 m2 and a very large resistance is in a 0.047-T uniform magnetic field oriented so that th

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A ten-loop coil having an area of 0.23 m2 and a very large resistance is in a 0.047-T uniform magnetic field oriented so that th

e maximum flux goes through the coil. The coil is then rotated so that the flux through it goes to zero in 0.34 s. What is the magnitude of the average emf induced in the coil during the 0.34 s? A ten-loop coil having an area of 0.23 m2 and a very large resistance is in a 0.047-T uniform magnetic field oriented so that the maximum flux goes through the coil. The coil is then rotated so that the flux through it goes to zero in 0.34 s. What is the magnitude of the average emf induced in the coil during the 0.34 s? 0.00 V 0.0032 V 0.032 V 0.32 V 1.0 V

Physics

1 answer:

Keith_Richards [3.2K] · Answer 1 · 2026-02-21T19:34:37+03:00

Answer:

The average induced emf in the coil is roughly 0.32 V.

Explanation:

Number of loops = N = 10

Area = 0.23 m²

Magnetic field = B = 0.047 T

Δt = 0.34 s

These are the provided values to compute EMF. The formula for emf is:

emf = e = N×ΔΦ/Δt

Therefore, ΔΦ = B. ΔA = BΔAcos(θ)

Since the flux is at its highest, θ = 0 and cos(0) = 1

Thus,

ΔΦ = BA

e = N×(BΔA)/Δt

e = 10×(0.047×0.23)/0.34

e = 0.317 V.

<pHence, rounding the figure gives

e ≅ 0.32 V.