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Natali5045456
6 days ago
14

Calculate the weight of a 4.5 kg rabbit.

Physics
1 answer:
Yuliya22 [2.4K]6 days ago
3 0
The answer is 13900589.
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Argelia has a stack of schoolbooks sitting in the backseat of her car. When Argelia makes a sharp right turn, the books slide to
Yuliya22 [2438]

Answer:

The books are displaced to the left due to inertia and ultimately halt when impacted by the car door.

Explanation:

The movement of the books can be understood through Newton's first two laws:

- The first law (Law of Inertia): an object will remain at rest or continue moving in a straight line unless an unbalanced force acts upon it.

- The second law: if unbalanced forces act on an object, it experiences an acceleration that can be described by the formula

F=ma

where F is the object's net force, m its mass, and a its acceleration.

Now let's relate this to the scenario:

- When Argelia makes a sharp right turn, the books, which are not secured in the car, maintain their straight-line motion due to inertia so they appear to move left as the car shifts right.

- Upon contacting the car door, the books cease moving due to the second law: the door exerts an unbalanced force, causing the books to decelerate and ultimately come to rest.

4 0
1 month ago
Read 2 more answers
An apple falls from an apple tree growing on a 20° slope. The apple hits the ground with an impact velocity of 16.2 m/s straight
serg [2593]

An apple strikes the ground at a velocity of 16.2 m/s.

The angle between the velocity of the apple and a line normal to the inclined surface is 20 degrees.

The parallel and perpendicular components of its velocity concerning the surface are as follows:

v_{perpendicular} = v cos20

v_{parallel} = v sin20

This gives us:

v_{parallel} = 16.2 sin20

v_{parallel} = 5.5 m/s

The velocity along the inclined plane measures 5.5 m/s.

7 0
1 month ago
A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. i
inna [2210]
In physics, acceleration describes how an object's velocity changes over time. Whenever the speed of an object shifts, it's considered to be accelerating. To calculate acceleration here:

acceleration = (8.2 - 3.5) / 1.5 = 3.1 m/s²

I trust this answers your question.
5 0
1 month ago
Read 2 more answers
A child wants to pump up a bicycle tire so that its pressure is 1.2 × 105 pa above that of atmospheric pressure. if the child us
kicyunya [2264]
The general formula is;
Pressure = Force/Area
Where,
Pressure = Required pressure + Atmospheric pressure = (1.2*10^5) + (101325) = 221325 Pa = 221325 N/m^2

Area = πD²/4 = π*0.035²/4 = 9.621*10^-4 m²

Thus,
Force, F = Pressure*Area = 221325*9.621*10^-4 = 212.94 N
7 0
24 days ago
Read 2 more answers
(a) A 15.0 kg block is released from rest at point A in the figure below. The track is frictionless except for the portion betwe
serg [2593]

Answer:

(a) the coefficient of friction is 0.451

This was derived using the energy conservation principle (the total energy in a closed system remains constant).

(b) No, the object stops 5.35 m away from point B. This is due to the spring's expansion only performing 43 J of work on the block, which isn't sufficient compared to the 398 J required to overcome friction.

Explanation:

For more details on how this issue was resolved, refer to the attached material. The solution for part (a) separates the body’s movement into two segments: from point A to B, and from B to C. The total system energy originates from the initial gravitational potential energy, which transforms into work against friction and into work compressing the spring. A work of 398 J is needed to counteract friction over the distance of 6.00 m. The energy used for this is lost since friction is not a conservative force, leaving only 43 J for spring compression. When the spring expands, it exerts a work of 43 J back on the block, which is only sufficient to move it through a distance of 0.65 m, stopping 5.35 m short of point B.

Thank you for your attention; I trust this is beneficial to you.

4 0
20 days ago
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