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likoan
2 months ago
7

Según la Organización Mundial de la Salud, el nitrato de plata ( densidad = 4.35 g/cc ) es una sustancia con propiedades cáustic

as, astringente, antiséptica y antiinfecciosa que apenas puede absorberse por la piel. Calcular la cantidad de agua necesaria para preparar 800 mL de una disolución 2 M de nitrato de plata. Ayuda porfavor
Chemistry
1 answer:
castortr0y [3K]2 months ago
8 0

Respuesta:

737.52 mL de agua

Justificación:

En este escenario, es necesario aplicar la fórmula de molaridad de una solución, que es:

M = moles / V

Donde:

V: Volumen de la solución.

Ya que deseamos determinar la cantidad de agua, en otras palabras, buscamos el volumen del solvente que se utilizó para crear los 800 mL de la disolución.

Una disolución se compone de un soluto y un solvente. El soluto que tenemos es nitrato de plata. Utilizando la fórmula mencionada, calculamos los moles de soluto y luego su masa. Tras eso, calculamos el volumen a partir de la densidad y, al final, determinamos la cantidad de solvente de esta manera:

V ste = Vsol - Vsto

Primero, vamos a calcular los moles de soluto:

moles = M * V

moles = 2 * 0.800 = 1.6 moles

Con este número de moles, obtenemos la masa utilizando el peso molecular que es 169.87 g/mol:

m = moles * PM

m = 1.6 * 169.87 = 271.792 g

Usando el valor de densidad, procederemos a calcular el volumen de soluto utilizado:

d = m/V

V = m/d

V = 271.792 / 4.35

V = 62.48 mL

Por último, la cantidad de agua requerida es:

V agua = 800 - 62.48

V agua = 737.52 mL

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