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Rina8888
1 day ago
8

You are given a piece of paper and a match. The paper has a mass of 2.5 g. You then light the match and light the piece of paper

on fire. After it burns, the remaining bits of paper weigh 0.5 g. Does this demonstration violate the conservation of mass? Explain why or why not?
Chemistry
1 answer:
KiRa [971]1 day ago
5 0

Answer:

No

Explanation:

No. The demonstration in question does not infringe upon the conservation of mass.

The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction; however, mass can change from one form to another during the process.

In this instance, although the remnants of the paper weigh 0.5 g compared to the original weight of 2.5 g, the ashes and gases produced during combustion account for the missing mass of the paper.

The portion that has been burnt has transformed into other states. If the gas and ashes are adequately contained, they will correspond to the weight of the original paper when added to the remaining paper.

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If 3.18 x 10^23 atoms of iron react with 67.2 L of chlorine gas at STP, what is the maximum
Tems11 [846]

84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.

Explanation:

Balanced equation:

2 Fe + 3 Cl2 → 2 FeCl3​

DATA PROVIDED:

iron =  atoms

mass of chlorine = 67.2 liters

mass of FeCl3 =?

The number of moles of iron will be calculated as

number of moles = \frac{total number of atoms}{Avagaro's number}

number of moles = \frac{3.18 x 10^23}{6.022x 10^23}

number of moles = 0.52 mol of iron

moles of chlorine gas

number of moles = \frac{mass}{molar mass of 1 mole}

Substituting the values into the equation:

n = \frac{67200}{70.96}               (molar mass of chlorine gas = 70.96 g/mol)

   = 947.01 moles

As iron is the limiting reagent therefore

2 moles of Fe lead to 2 moles of FeCl3

0.52 moles of Fe will yield

\frac{2}{2} = \frac{x}{0.52}

0.52 moles of FeCl3 is produced.

To express this in grams:

mass = n x molar mass

         = 0.52 x 162.2                   (molar mass of FeCl3 is 162.2g/mol)  

          = 84.34 grams        

3 0
3 days ago
An unknown liquid has a mass of 4.25 × 108 mg and a volume of 0.250 m3. what is the density of the liquid in units of g/ml?
VMariaS [1037]
Density is calculated as mass divided by volume.
  Step one:
Convert m³ to ml.
1 m³ = 1,000,000 ml
0.250 m³ x 1,000,000 = 250,000 ml
  Step two: Convert mg to g.
1 mg = 0.001 g, hence 4.25 x 10^8 mg equals 0.459 g.
Consequently, the density comes out to be 0.459 g/250,000 = 1.836 x 10^-6 g/ml.
8 0
4 days ago
Read 2 more answers
A metallic object holds a charge of −4.8 × 10−6 C. What total number of electrons does this represent? (e = 1.6 × 10−19 C is the
Anarel [852]

Answer:

n=3.0\times 10^{13}

Explanation:

Charge of one electron = -1.6\times 10^{-19}\ C

The formula for calculating charge is:

Charge=n\times q_e

Given that: Charge = -4.8\times 10^{-6}\ C

-4.8\times 10^{-6}=n\times (-1.6\times 10^{-19})

n=\frac{4.8\times 10^{-6}}{1.6\times 10^{-19}}=3.0\times 10^{13}

Total electrons, n = 3.0\times 10^{13}

5 0
13 days ago
The molar absorptivity of a compound at 500 nm wavelength is 252 M-1cm-1. Suppose one prepares a solution by dissolving 0.00140
lorasvet [956]

Answer:

The solution's absorbance measures 0.21168.

Explanation:

Provided that,

Wavelength = 500 nm

Molar absorptivity = 252 M⁻¹ cm⁻¹

Moles present = 0.00140

Total solution volume = 500.0 mL

Path length = 3.00 mm

We have to determine the molar concentration

Utilizing the formula for molar concentration

C=\dfrac{N}{V}

Where N = number of moles

V = volume

Input the values into the formula

C=\dfrac{0.00140}{0.5000}

C=0.0028\ M

Next, we will calculate the solution's absorbance

Using the absorbance formula

A=\epsilon C l

Substituting values into the equation

A=252\times0.0028\times0.300

A=0.21168

Therefore, the absorbance of the solution is 0.21168.

5 0
15 days ago
A food worker had safely cooled a large pot of soup to 70 F (21 C) with two hours. What temperature must the soup Reach in the f
lorasvet [956]

After four hours of cooling, the soup reached a temperature of 140 F (or) 42 C.

Explanation:

A food worker allowed a cup of soup to cool for two hours,

step 1: The temperature attained in two hours is 70 F (or) 21 C

step 2: Consequently, in four hours, this doubles the value

Therefore, the temperature after four hours is 2(70)= 140 F (or) 2(21)= 42 C

4 0
11 days ago
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