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xxTIMURxx
3 months ago
15

Write a hypothesis for Part II of the lab, which is about the type of material an object is made of, and its ability to absorb o

r release thermal energy. Use the format of "if . . . then . . . because . . .” and be sure to answer this part of the lesson question: "How does the type of material affect thermal energy transfer?”
Chemistry
2 answers:
castortr0y [3K]3 months ago
5 0

Answer:

Various materials will exhibit different temperature changes when subjected to an equal amount of thermal energy. This occurs because each material has its distinct specific heat.

Explanation:

that is the answer

Tems11 [2.7K]3 months ago
5 0

Answer:

For the second part of the lab, my hypothesis would be

Explanation:

If materials of equal volume are subjected to the same thermal energy, then they will transfer varying amounts of energy, given that each substance possesses a specific heat unique to it.

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Heavy nuclides with too few neutrons to be in the band of stability are most likely to decay by what mode?
Anarel [2989]

Answer:

Positron emission

Explanation:

In positron emission, a proton transforms into a neutron. This alteration results in a daughter nucleus with its mass number increased by 1, while the atomic number remains unchanged. The formation of a new neutron boosts the neutron count in the daughter nucleus, thus enhancing the N/P ratio.

Concurrently, a positron is emitted along with an anti-neutrino to ensure spin conservation.

6 0
2 months ago
Calculate the mass, in grams, of a single tellurium atom (mte = 127.60 amu ).
castortr0y [3046]

1 atomic mass unit (amu) represents the mass of an atom or is used to measure mass on an atomic scale. It is also referred to as a dalton, abbreviated as Da, while atomic mass unit is indicated as amu.

1 amu can be translated into grams as follows:

1 amu = 1.6 * 10^-2^4 g

Mass of Te = 127.6 amu

For conversion into grams:

M = (127.6 ) * 1.6 * 10^-2^4 g

M = 204.16 * 10^-2^4 g

Therefore, the mass of Te is 204.16 * 10^-2^4 g

8 0
3 months ago
Read 2 more answers
45.0 g of Ca(NO3)2 are used to create a 1.3 M solution. What is the volume of the solution
Tems11 [2777]
The formula for Molarity is given by:

                                  M = moles / V
To isolate V,
                              V = moles / M ------------------(1)
Moles can also be calculated as:
                                  moles = mass / M.mass -------------(2)
Substituting the value of moles from equation 2 into equation 1 yields:
                                  V = (mass / M.mass) / M
Plugging in the numbers gives:
                                  V = (45 g / 164 g/mol) / 1.3 mol/dm³

                                       V = 0.21 dm³.
6 0
3 months ago
Calculate ΔH and ΔStot when two copper blocks, each of mass 10.0 kg, one at 100°C and the other at 0°C, are placed in contact in
eduard [2782]

Clarification:

The pertinent information is outlined as follows.

m = 10.0 kg = 10,000 g (since 1 kg = 1000 g)

Starting temperature of block 1, T_{1} = 100^{o}C = (100 + 273) K = 373 K

Starting temperature of block 2, T_{2} = 0^{o}C = (0 + 273) K = 273 K

Therefore, the heat lost by block 1 equals the heat received by block 2

mC \Delta T = mC \times \Delta T

10000 g \times 0.385 \times (T_{f} - 100)^{o}C = 10000 g \times 0.385 \times (0 - T_{f})^{o}C

T_{f} - 100^{o}C = 0^{o}C - T_{f}

2T_{f} = 100^{o}C

T_{f} = 50^{o}C

It's important to convert the temperature into Kelvin as (50 + 273) K = 323 K.

Additionally, the relationship between enthalpy and temperature change is as follows.

\Delta H = mC \Delta T

= 10000 g \times 0.385 J/K g \times 323 K

= 1243550 J

or, = 1243.5 kJ

Next, determine the entropy change for block 1 as follows.

\Delta S_{1} = mC ln \frac{T_{f}}{T_{i}}

= 10000 g \times 0.385 J/K g \times ln \frac{323}{373}

= 10000 g \times 0.385 J/K g \times -0.143

= -554.12 J/K

Now, the entropy change for block 2 is as follows.

   \Delta S_{2} = mC ln \frac{T_{f}}{T_{i}}

           = 10000 g \times 0.385 J/K g \times ln \frac{323}{273}

           = 10000 g \times 0.385 J/K g \times 0.168

           = 647.49 J/K

Thus, the total entropy is the sum of the entropy changes of both blocks.

                   = -554.12 J/K + 647.49 J/K\Delta S_{total} = \Delta S_{1} + \Delta S_{2}

           = 93.37 J/K

In conclusion, for this reaction, the outcome is 1243.5 kJ and \Delta S_{total} is 93.37 J/K.

6 0
3 months ago
How many molecules are in 13.5g of sulfur dioxide, so2?
alisha [2963]
Answer: The number of sulfur dioxide molecules present is 1.27·10²³.
Calculating: m(SO₂) equals 13.5 g.
Using the formula n(SO₂) = m(SO₂) ÷ M(SO₂).
This gives n(SO₂) = 13.5 g ÷ 64 g/mol.
Resulting in n(SO₂) = 0.21 mol.
Subsequently, N(SO₂) = n(SO₂) ·Na.
Therefore, N(SO₂) = 0.21 mol · 6.022·10²³ 1/mol.
Ultimately, N(SO₂) equals 1.27·10²³.
Where n represents amount of substance.
M refers to molar mass.
Na is Avogadro's number.
5 0
3 months ago
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