Answer:
The calculated volume of a lithium atom is 1.47 X 10⁻²⁹ m³.
Explanation:
Assuming the atom's volume is spherical (though it’s actually more complex), the volume is mathematically represented by:
----------------------------------------------------------------------------------------(Eq. 1)
Here, R corresponds to the lithium atom's radius. Since the radius is provided in picometers, we first convert it into meters.
Substituting this value into Eq.1 provides the desired result.
V= 1.47 X 10⁻²⁹ m³
Answer:
In blood: Dispersed phase: blood cells; Dispersed medium: liquid plasma
In fruit jelly: Dispersed phase: fruit juice; Dispersed medium: pectin
Explanation:
The dispersed phase refers to the phase where colloidal particles are dispersed within another phase, known as the dispersion medium.
In blood, the tiny cells act as colloidal particles, forming the dispersed phase within the liquid medium identified as plasma.
Conversely, in fruit jelly, the fruit juice constitutes the dispersed phase while the solid pectin serves as the dispersed medium.
Step
: To find the mass of a single washer, divide the total measured mass by the number of washers
. Step
: Convert kilograms to milligrams knowing
; thus
resulting in the final answer
.
Response:
Here's my calculation
Clarification:
Assume the starting concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.
We need to determine the initial concentration of HI.
1. We will need a chemical equation with concentrations, so let's compile all the information in one location.
H₂ + I₂ ⇌ 2HI
I/mol·L⁻¹: 0.30 0.15 x
2. Calculate the concentration of HI
![Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} = 5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}](https://tex.z-dn.net/?f=Q_%7B%5Ctext%7Bc%7D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BHI%5D%7D%5E%7B2%7D%7D%20%7B%5Ctext%7B%5BH%24_%7B2%7D%24%5D%5BI%24_%7B2%7D%24%5D%7D%7D%20%3D%5Cdfrac%7Bx%5E%7B2%7D%7D%7B0.30%20%5Ctimes%200.15%7D%20%3D%20%205.56%5C%5C%5C%5Cx%5E%7B2%7D%20%3D%200.30%20%5Ctimes%200.15%20%5Ctimes%205.56%20%3D%200.250%5C%5Cx%20%3D%20%5Csqrt%7B0.250%7D%20%3D%20%5Ctextbf%7B0.50%20mol%2FL%7D%5C%5C%5Ctext%7BThe%20initial%20concentration%20of%20HI%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B0.50%20mol%2FL%7D%7D%24%7D)
3. Plot the initial values
The graph below visualizes the initial concentrations as plotted on the vertical axis.
