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Harrizon
3 months ago
11

A helium ion of mass 4m and charge 2e is accelerated from rest through a potential difference V in vacuum. Its final speed will

be
​
Physics
1 answer:
kicyunya [3.2K]3 months ago
3 0
The helium ion carries a charge of 2e, a mass of 4m, and accelerates through a potential difference V in a vacuum. From electrostatic principles, the work done correlates to the product of the charge and its potential difference. Thus, the work done equates to charge multiplied by potential difference, which results in 2eV. This work results in kinetic energy, leading to the relation: Work done = Kinetic energy.
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Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 4.00. What should be the length of B⃗ so that th
serg [3582]

Answer:

B= \sqrt{65} ≅8.06

Explanation:

Applying the Pythagorean theorem:

C^{2}= A^{2} + B^{2}

Here, C denotes the hypotenuse length, while A and B signify the lengths of the other two sides of the triangle. We can calculate B's length knowing the hypotenuse is 9 and A is 4.

9^{2}=4^{2} + B^{2}

81= 16+ B^{2}

81-16= B^{2}

B= \sqrt{65} ≅8.06

8 0
4 months ago
Suppose you are designing an amplifier and loudspeaker system to use at a rock concert. You want to make it as loud as possible.
Softa [3030]
The response is outlined below. Audio power amplifiers are present in various sound systems, including those for sound reinforcement, public addresses, home audio, and musical instrument amplifiers like those for guitars. This component is the final electronic element in the audio playback chain before signals reach the loudspeaker. To achieve the loudest possible sound, it is essential to maximize output while maintaining high input and low output impedance.
4 0
2 months ago
A neutral K meson at rest decays into two π mesons, which travel in opposite directions along the x axis with speeds of 0.828c.
Sav [3153]

Answer:

The velocities of both \pi-mesons are 0.574 in the positive direction and -0.9367c in the negative direction along the X-axis

Solution:

Referring to the question:

The speed of the \pi-meson is v' = 0.828c

And the K-meson's speed in the positive x direction is v'' = 0.486c

Now, to determine the speeds of the two \pi-mesons:

Velocity of the first \pi-meson, v_{px}:

v_{px} = \frac{v' - v''}{1 - \frac{v'v''}{c^{2}}}

v_{px} = \frac{0.828c - 0.486c}{1 - \frac{0.828c\times 0.486c}{c^{2}}}

v_{px} = \frac{0.828c - 0.486c}{1 - \frac{0.828c\times 0.486c}{c^{2}}}

v_{px} = 0.574c

Velocity of the second \pi-meson, v_{px}:

v_{px} = \frac{v' - v''}{1 - \frac{v'v''}{c^{2}}}

v_{px} = \frac{- 0.828c - 0.486c}{1 + \frac{0.828c\times 0.486c}{c^{2}}}

v'_{px} = \frac{- 0.828c - 0.486c}{1 + \frac{0.828c\times 0.486c}{c^{2}}}

v'_{px} = - 0.937c

6 0
2 months ago
Read 2 more answers
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