Response: Below are the orbitals responsible for each bond identified in citric acid per the attachment.
Response 1) σ Bond a: Carbon uses 
and Oxygen employs .
Clarification: The sigma bonds are formed through the hybrid orbitals of carbon and oxygen. This occurs at the 'a' location in the citric acid structure.
Response 2) π Bond a: Both Carbon and Oxygen have π orbitals.
Clarification: The π-bond at position 'a' consists of interactions between the π orbitals of carbon and oxygen.
Response 3) Bond b: Oxygen 
and Hydrogen solely utilizes the S orbital.
Clarification: The bonding at position 'b' includes oxygen and hydrogen atoms, with hydrogen utilizing its S orbital.
Response 4) Bond c: Carbon is and Oxygen is also .
Clarification: The bonding process at position 'c' involves both carbon and oxygen atoms with their respective hybrid orbitals.
Response 5) Bond d: Carbon atom has and the second carbon has .
Clarification: In position 'd', the bond formed between carbon atoms is , utilizing orbitals that underwent hybridization which are .
Response 6) Bond e: C1 has O .
C2 has .
Clarification: The carbon that contains oxygen and a double bond utilizes hybridized orbitals; conversely, carbon at C2 employs hybridized orbitals in this bonding at position 'e'.
![pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D%20%29%20)
![\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BCH_3COOH%5D%7D%7B%5BCH_3COONa%7D%3D%2010%5E%7B%28pH-pKa%29%5E%7B-1%7D%7D%3D10%5E%7B%284-4%2C76%29%5E%7B-1%7D%7D%3D5%2C75%20)
