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vova2212
2 months ago
9

mixture or pure substance: 1.blood 2.dyes 3.self-raising flour 4.muesli 5.copper wire 6.distilled water 7.table salt 8.milk 9.br

onze 10.tea 11.oxygen 12.air
Chemistry
1 answer:
alisha [2.9K]2 months ago
5 0

Answer: Mixture: Blood, Self raising flour,muesli,dyes, milk, tea, air, bronze

Pure substance: Copper wire, distilled water, table salt, oxygen.

Explanation:

A mixture is a substance composed of two or more compounds which are chemically independent and keep their individual chemical properties.

Examples: Blood, Self raising flour,muesli,dyes, milk, tea, air, bronze

A pure substance is defined as something with a uniform and constant composition and is called a pure substance.

Examples: Copper wire, distilled water, table salt, oxygen.

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Which best describes the relationships between subatomic particles in any neutral atom? * 1 point the number of electrons equals
Tems11 [2777]

The atomic number corresponds to the number of protons

Protons are denoted as P and Electrons as E P = E

The atomic mass equals the sum of Neutrons and Protons

Atomic number = atomic mass = neutrons

P = E

Atomic mass - atomic number = Neutrons

Example:

Calcium consists of 20 Protons 20P = 20E

Atomic mass - atomic number = neutron count:)

4 0
1 month ago
The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr
lions [2927]

Response:

The pKa value is 13.0.

Clarification:

pKa + pKb = 14

For trimethylamine, Kb = 6.3 × 10^{-5}

Calculating pKb: pKb = - log (6.3 × 10^{-5})

= 1.0

Thus, pKa = 14 - pKb = 14 - 1.0

pKa = 13.0

Verification: The typical range for pKa in weak acids is from 2 to 13.

8 0
2 months ago
Dicarbon monoxide, C2O, is found in dust clouds in space. Analysis of it shows that the sequence of atoms in this molecule is C–
castortr0y [3046]

Greetings,


The number of lone pairs of electrons in a C2O molecule is...

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8 0
2 months ago
Read 2 more answers
In living organisms, C-14 atoms disintegrate at a rate of 15.3 atoms per minute per gram of carbon. A charcoal sample from an ar
lions [2927]

Answer:

The result is "4,241.17 years"

Explanation:

The disintegration rate for C-14 atoms is indicated in  15.3 \frac{atoms}{min-g}

The dissolution rate of the sample is given by 9.16 \frac{atoms} {min-gram}

The C-14 proportion within the sample can be determined as per = \frac {9.16}{15.3} \\\\ = 0.5987

With a half-life of 5730 years.

Now, we need to compute the number of half-lives (n) that are applicable:

(\frac{1}{2})^n= A\\\\A= fraction of C-14, which is remaining \\\\(\frac{1}{2})^n= 0.5987 \\\\ n \log 2 = - \log 0.5987\\\\

\therefore \\\\ \Rightarrow n= \frac{0.227}{0.3010} \\\\ = 0.740\\

Thus, the age of the sample is represented as = n \times\ half-life

                                                 = 0.740 \times 5730 \ years \\\\=4241.17 \ years\\\\

6 0
2 months ago
The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. What is this distance in mil
lorasvet [2795]

Answer:

C) 1.15 × 10⁻⁷ mm

Explanation:

Step 1: Provided information

Average separation between oxygen and nitrogen atoms: 115 pm

Step 2: Change the distance to meters (SI standard unit)

Using the conversion 1 m = 10¹² pm.

115 pm × (1 m/10¹² pm) = 1.15 × 10⁻¹⁰ m

Step 3: Transform the distance to millimeters

Employing the conversion 1 m = 10³ mm.

1.15 × 10⁻¹⁰ m × (10³ mm/1 m) = 1.15 × 10⁻⁷ mm

5 0
1 month ago
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