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vladimir2022
2 months ago
14

Dumbledore decides to gives a surprise demonstration. He starts with a hydrate of Na2CO3 which has a mass of 4.31 g before heati

ng. After he heats it he finds the mass of the anhydrous compound is found to be 3.22 g. He asks everyone in class to determine the integer x in the hydrate: Na2CO3·xH2O; you should do this also. Round your answer to the nearest integ
Chemistry
1 answer:
eduard [2.7K]2 months ago
7 0
The formula is Na₂CO₃·2H₂O. To find the integer x representing the amount of crystallization water, we analyze the given mass before and after heating.
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A 3.5 kg iron shovel is left outside through the winter. The shovel, now orange with rust, is rediscovered in the spring. Its ma
alisha [2963]
a
8 0
1 month ago
Researchers stationed at different areas on a mountain and in a tunnel midway through the mountain boiled water at the same time
VMariaS [2998]

Moving on to the second issue

Let's tackle the second question first. Once you grasp that, the first question will be simpler. By the way, this is an excellent question to clarify. The concepts of less than and more than can be quite tricky in the sciences. Every question you encounter that utilizes less or more should be approached with caution.

As altitude increases, air pressure decreases (essential term: less highlight this sentence in color. Take a moment to reflect on it.)

As the pressure declines, less energy (again, key term) is required for water molecules to escape the surface. Thus, the boiling temperature is lower than it would be at sea level.

Answer to problem two: Lower

Problem One

Water reaches its boiling point when the greatest number of molecules can leave the water's surface. Equal to is the right answer.  Although pinpointing the exact answer can be challenging, equal to is indeed the correct response.

6 0
2 months ago
27. How much energy is required to change 150.0 g of water from 10.0°C to 45.0°C? (Cwater =
Alekssandra [3086]

Answer:

The correct option is C. 21900.3. I calculated 21945 J, which makes option C closely aligned with my result.

Explanation:

Data

mass = 150 g

initial temperature T1 = 10°C

final temperature T2 = 45°C

Cw = 4.18 J/g°C

Formula

Q = mCΔT = mC(T2 - T1)

Substitution

Q = (150)(4.18)(45 - 10)

Simplification

Q = (150)(4.18)(35)

Result

Q = 21945 J

5 0
1 month ago
The volume of a gas at 6.0 atm is 2.5 L. What is the volume of the gas at 7.5 atm at the same temperature?
castortr0y [3046]

Greetings!

The result is:

The new volume is: 2L

Rationale:

Because the temperature remains constant, we can apply Boyle's Law to solve this issue.

Boyle's Law stipulates that:

P_{1}V_{1}=P_{2}V_{2}

Where,

P is the gas's pressure.

V is the gas's volume.

According to the information provided:

V_{1}=2.5L\\P_{1}=6.0atm\\P_{2}=7.5atm

Let's put the values into the equation:

2.5L*6.0atm=7.5atm*V_{2}

2.5L*6.0atm=7.5atm*V_{2}\\\\V_{2}=\frac{2.5L*6.0atm}{7.5atm}=\frac{15L.atm}{7.5atm}=2L

Consequently, the new volume is: 2L

Wishing you a lovely day!

7 0
2 months ago
The elements X and Y combine in different ratios to form four different types of compounds: XY, XY2, XY3, and XY4. Consider that
eduard [2782]

Answer:

The ratios arranged in ascending order are; The ratio of the mass of Y to X in XY2 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY3 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY4 divided by the mass of Y to X in XY

1) Mass ratio = 3

2) Mass ratio = 2

3) Mass ratio = 4

Explanation:

Comprehensive calculations are displayed in the attachment.

3 0
2 months ago
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