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1 day ago

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Imagine you derive the following expression by analyzing the physics of a particular system: a=gsinθ−μkgcosθ, where g=9.80meter/

second2. Simplify the expression for a by pulling out the common factor.
a.) a = g sinθ − μk g cosθ (no simplification should be performed on the expression in this situation)

b.) a = g (sinθ−μk cosθ)

c.) a = (9.80meter/second^2)sinθ −μk (9.80 meter/second^2)cosθ

1 answer:

Sav [1K]1 day ago

8 0

Answer:

Explanation:

Examining the derived equation reveals

a=gsinθ−μkgcosθ

All components in this formulation are accurate, but further simplification is achievable.

We can explore additional simplification within the equation.

<pby analyzing="" the="" right="" side="" we="" see="" that="" gravity="" is="" a="" common="" factor="" on="" both="" terms="" hence="" can="" it="" out:="">

This makes option a incorrect, as further simplifications yield

a=g(sinθ−μkcosθ)

Option b is valid and represents the optimal choice.

Since we are provided with g=9.8m/s²

we can also input this into option a

<presulting in="">

a=9.8m/s²(sinθ−μkcosθ)

Option C also holds but is less preferred as it substitutes the gravity value directly without prior simplification.

The optimal form would be

a=9.8m/s²(sinθ−μkcosθ)

Thus, the best choice is B.

</presulting></pby>

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The string does not experience any force of tension, as it balances two forces acting in the same direction. Hence, the tension is zero.

Explanation:

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A camera operator is filming a nature explorer in the Rocky Mountains. The explorer needs to swim across a river to his campsite

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Answer:

a. Angle= 28.82°

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Explanation:

Velocity Vector

Velocity is a measure of how quickly something is moving in a specific direction. It is represented as a vector that has both magnitude and direction. If an object can only move in one direction, then speed can serve as the scalar equivalent of that velocity (only focusing on magnitude).

a.

The explorer aims to swim across a river to reach his campsite, as depicted in the image below. The river's velocity is vr and the explorer's swimming speed in still water is ve. If he were to swim straight towards the campsite, he would end up downstream due to the river's current. Therefore, he must swim at an angle that allows him to overcome the current while still moving towards his goal. This angle relative to the shore is what we need to determine. The explorer's speed can be broken down into its horizontal (vx) and vertical (vy) components. In order to counteract the river's flow:

$v_{ey}=v_r$

We can calculate the vertical component of the explorer's swimming speed as

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b.

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