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2 months ago

For a proton (mass = 1.673 x 10–27 kg) moving with a velocity of 2.83 x 104 m/s, what is the de Broglie wavelength (in pm)?

1 answer:

6 0

The calculated de Broglie wavelength is 14.0 pm. Given the mass of a proton at 1.673 x 10⁻²⁷ kg and its velocity of 2.83 x 10⁴ m/s, the de Broglie wavelength is derived from the formula defined by Planck's constant.

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Liam throws a water balloon horizontally at 8.2 m/s out of a window 18 m from the ground.

Yuliya22 [3333]

The time required for the water balloon to reach the ground is given as

$h = \frac{1}{2} gt^2$

Here we understand that

$h = 18 m$

$g = 9.8 m/s^2$

Now applying the earlier mentioned formula

$18 = \frac{1}{2}*9.8* t^2$

$18 = 4.9 t^2$

$t = 1.92 s$

Now in the same time frame, we can conclude the distance covered will be

$d = v_x * t$

$d = 8.2 * 1.92 = 15.7 m$

Thus, it will land at a distance of 15.7 m from where it started

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2 months ago

A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i

Sav [3153]

Respuesta:

11.4 m/s

Explicación:

La fórmula para la aceleración centrípeta es:

$a=\frac{v^2}{R}$

donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.

En este problema,

a = g = aceleración debida a la gravedad en la cima = $9.81\ m/s^2$

v = ?

R = 13.2 m

Por lo tanto,

$9.81=\frac{v^2}{13.2}$

$v^2=9.81\times {13.2}$

v = 11.4 m/s

8 0

3 months ago