Answer:
602.27 kg
Explanation:
Below is the calculation for determining the maximum cargo weight the balloon can lift:
Helium volume within the balloon = (4 ÷ 3) × π × r^3
= (4 ÷ 3) × 3.14 × 6.953
= 1406.19 m³
Maximum lift capacity of the balloon = volume × (density of air - density of helium)
= 1406.19 × (1.29 - 0.179)
= 1562.27 kg
The maximum cargo weight it can carry is calculated as: Cargo capacity - Weight of structure
= 1562.27 - 960
= 602.27 kg
Answer:
Explanation:
An atom comprises three distinct particles: electrons, protons, and neutrons.
These particles vary in mass and electric charge, contributing to the atom's characteristics.
Electrons bear a negative charge, protons are positively charged, and neutrons possess no charge. An atom is electrically neutral when it has an equal number of electrons and protons, but this can change if particles are removed.
1: Ionized atom model - an ionized atom carries a net charge, which can be positive or negative.
To illustrate an ionized atom, one would need to reduce the number of either electrons or protons.
2: Radioactive atom model: A radioactive atom is characterized as unstable and retains excess energy in its nucleus, often due to added neutrons or protons.
Answer:
Explanation:
By applying the Law of Sines,
Based on Newton's Law,
And the final equation also derived from Newton's Law,
Then by consolidating all the equations together,
Thus,
Answer:
1.5 m/s²
Explanation:
Begin by sketching a free body diagram. Three forces are at play on the sea lion: the force of gravity acting downwards, the normal force that is perpendicular to the ramp, and the frictional force parallel to the ramp.
Considering the forces perpendicular to the incline:
∑F = ma
N − mg cos θ = 0
This gives us N = mg cos θ
Next, examining the forces parallel to the incline:
∑F = ma
mg sin θ − Nμ = ma
Substituting for N yields:
mg sin θ − (mg cos θ) μ = ma
g sin θ − g cos θ μ = a
hence a = g (sin θ − μ cos θ)
If we set θ = 23° and μ = 0.26:
a = 9.8 (sin 23 − 0.26 cos 23)
this results in a = 1.48
When rounded to two significant figures, the acceleration of the sea lion is 1.5 m/s².
