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juin
1 month ago
8

Calculate the molarity of 48.0 mL of 6.00 M H2SO4 diluted to 0.250 L

Chemistry
2 answers:
lorasvet [2.7K]1 month ago
4 0

Answer:

The molality is 1.15 m.

Molality is calculated by dividing the number of moles of solute by the kilograms of solvent, which in this case is water.

Calculate moles of H₂SO₄ from molarity:

C = n/V → n = C × V = 6.00 mol/L × 0.048 L = 0.288 moles

Mass of solvent (water) based on density:

m = ρ × V = 1.00 kg/L × 0.250 L = 0.250 kg

Therefore, molality is:

m = moles/solvent mass = 0.288 moles / 0.250 kg = 1.15 m

lions [2.9K]1 month ago
3 0

Answer:

The resulting molarity after diluting 48.0 mL of 6.00 M H₂SO₄ to 0.250 L is 1.152 M.

Explanation:

Dilution decreases concentration by adding more solvent while keeping the amount of solute constant, thereby increasing total volume.

Using the formula:

Initial moles = Final moles → MiVi = MfVf

Where:

  • Mi = initial molarity = 6 M
  • Vi = initial volume = 48 mL = 0.048 L
  • Mf = final molarity (unknown)
  • Vf = final volume = 0.250 L

Substitute values:

6 M × 0.048 L = Mf × 0.250 L

Solving for Mf:

Mf=\frac{6M*0.048L}{0.250 L}

Thus, Mf = 1.152 M

The concentration of the diluted H₂SO₄ solution is 1.152 M.

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