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sp2606
1 month ago
7

A measuring microscope is used to examine the interference pattern. It is found that the average distance between the centers of

adjacent dark fringes is 0.480 mm. Analysis Taking into consideration the phase changes that take place upon reflection, which of the following is the condition for destructive interference of the reflected light? 2t = m + 1 2 λair, m = 0, 1, 2, ... 2t = mλair, m = 0, 1, 2, ... Solve for the thickness d of the hair. µm
Physics
1 answer:
Maru [3.3K]1 month ago
3 0
2n t = m λ₀, R = 0.240 mm. The interference from thin films arises from two main rays: one reflecting off the surface and another from within the film. The ray reflected from the top experiences a 180º phase shift as it transitions from a material with a lower refractive index to one with a higher index. This phase shift results in a λ/2 change. Meanwhile, the ray traversing the film undergoes a wavelength alteration due to the medium's refractive index, where λ₀ = λ / n. Thus, considering this, the equation for destructive interference incorporates an integer phase shift leading to 2t = (m’+ ½ + ½) λ₀ / n and simplifying to 2t = (m’+1) λ₀ / n, with the conclusion that m = m’+ 1, resulting in 2n t = m λ₀, where m can be 0, 1, 2,... The thickness of the hair serves as the film’s thickness indicated by 2R = t, thereby concluding that R = t / 2 and results in R = 0.240 mm.
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