Weight of the object = 35 lbs
F = ma
m = F/a = 35/32 (with acceleration of 32 ft/s²)
m= 1.09
Again applying the same formula,
a = F/m
a= 6/1.09
a= 5.489
Thus, the acceleration is approximately 5.5 ft/s²!!
<span>E = h x f </span>
<span>Thus: </span>
<span>f = E / h </span>
<span>f = 4.41•10^-19 / 6.62•10^-34 </span>
<span>f = 6.66•10^14 Hz (s^-1) </span>
<span>b/ What is the wavelength of this light? </span>
<span>------------------------------ </span>
<span>λ = c / f </span>
<span>λ = 3•10^8 / 6.66•10^14 </span>
<span>λ = 4.50•10^-7 m </span>
Answer: 592.37m
Explanation:
Person D is represented by the blue line.
The total displacement is calculated by subtracting the initial position from the final position. Starting at (0,0), the path consists of moving down two blocks, then right six blocks, followed by moving up four blocks, and finally left one block.
Here, I consider the positive direction of the x-axis to the right and the positive direction of the y-axis as upward.
Thus, the new coordinates will be, with B representing a block:
P =(6*B - 1*B, -2*B + 4*B) = (5*B, 2*B)
Given that B = 110m
P = (550m, 220m)
The displacement corresponds to the length of the vector, since the change from the initial position (0,0) to P is simply P:
P = √(550^2 + 220^2) = 592.37m
<span>The work done corresponds to the potential energy that the person acquires while ascending the stairs.
work = potential energy acquired = mgh
W = 75kg * 9.8m/s² * 2.50m = 1837.5 J</span>
Esta pregunta está incompleta, la pregunta completa es;
La figura muestra un recipiente sellado en la parte superior por un pistón móvil. Dentro del recipiente hay un gas ideal a 1.00 atm. 20.0°C y 1.00 L.
"¿Cuál será la presión dentro del recipiente si el pistón se mueve hasta la marca de 1.60 L mientras se mantiene constante la temperatura del gas?"
Answer:
la presión dentro del recipiente será 0.625 atm si el pistón se mueve hasta la marca de 1.60 L manteniendo constante la temperatura del gas
Explicación:
Dado que;
P₁ = 1.00 atm
P₂ =?
V₁ = 1 L
V₂ = 1.60 L
la temperatura del gas se mantiene constante
sabemos que;
P₁V₁ = P₂V₂
por lo que hacemos la sustitución
1 × 1 = P₂ × 1.60
P₂ = 1 / 1.60
P₂ = 0.625 atm
Por lo tanto, la presión dentro del recipiente será 0.625 atm si el pistón se mueve hasta la marca de 1.60 L mientras la temperatura del gas se mantiene constante
