Assume that you stay on the earth's surface. what is the ratio of the sun's gravitational force on you to the earth's gravitatio

Answer:

The acceleration of the platform is - 1.8 m/s²

Explanation:

The net force on a body causes that body to accelerate in the direction of the resultant force applied.

Setting up the force equilibrium for the configuration:

ma = 800 - mg

100a = 800 - 100×9.8

100a = - 180

100a = - 180

a = - 1.8 m/s²

This indicates that the body is falling downward.

b ) The first lens is a concave lens with a focal length of f₁ = - 12 cm and an object distance of u = - 20 cm. Using the lens formula, 1 / v - 1 / u = 1 / f, we get 1 / v + 1 / 20 = -1 / 12. This leads to 1 / v = - 1 / 20 - 1 / 12, which simplifies to 1 / v = -0.05 - 0.08333, yielding v = -7.5 cm. Consequently, the first image is formed before the first lens, near the object side, which becomes the object for the second lens with a distance of 16.5 cm from the second lens. c ) For the second lens, object distance is u = -16.5 cm, and focal length f₂ = + 12 cm (convex lens). Using the lens formula leads to 1 / v + 1 / 16.5 = 1 / 12, and this results in 1 / v = 1 / 12 - 1 / 16.5, which simplifies to 1 / v = 0.08333 - 0.0606. Finally, we find v = 44 cm (approximately). This image will be formed on the other side of the convex lens, which is 53 cm from the first lens. Magnification by the first lens is v / u = -7.5 / -20 = 0.375. For the second lens, it is v / u = 44 / - 16.5 = -2.67. d ) The total magnification becomes 0.375 x - 2.67 = - 1.00125. The height of the final image is then calculated as 2.50 mm x 1.00125 = 2.503 mm. e ) The final image will be inverted compared to the object since the total magnification is negative.

a) The student's speed after jumping is 1.07 m/s

b) The final speed of the laser is 10.4 m/s

Explanation:

a)

This issue can be approached through the momentum conservation principle: In the absence of external forces, the combined momentum of the student and the laser must remain unchanged. Hence, we can express:

where:

The initial momentum is zero

m = 42 kg signifies the mass of the laser

v = 1.5 m/s is the laser's final velocity

M = 59 kg is the mass of the student

V denotes the student's final velocity

Solving this for V, we can determine the student's speed:

Thus, the student's final speed calculates to 1.07 m/s.

b)

Here, both the laser and the student have a combined speed of 3.1 m/s prior to the student's jump; thus, the initial momentum isn't zero.

<pSo, we formulate the equation of momentum conservation as:

where:

m = 42 kg denotes the mass of the laser

M = 59 kg is the student’s mass

u = 3.1 m/s is their starting velocity

V = -2.1 m/s indicates the student's speed post-jump (she jumps backward)

v signifies the laser's final speed

When we resolve for v, we have:

Learn more about momentum: