Answer:
Maximum emf = 5.32 V
Explanation:
Provided data includes:
Number of turns, N = 10
Radius of loop, r = 3 cm = 0.03 m
It made 60 revolutions each second
Magnetic field, B = 0.5 T
We are tasked to determine the maximum emf produced in the loop, which is founded on Faraday's law. The induced emf can be calculated by:

For the maximum emf, 
Therefore,

Hence, the maximum emf generated in the loop is 5.32 V.
Answer:
The response to your inquiry is: 15 m/s²
Explanation:
Equation x = at³ - bt² + ct
a = 4.1 m/s³
b = 2.2 m/s²
c = 1.7 m/s
First we calculate x at t = 4.1 s
x = 4.1(4.1)³ - 2.2(4.1)² + 1.7(4.1)
x = 4.1(68.921) - 2.2(16.81) + 6.97
x = 282.58 - 36.98 + 6.98
x = 252.58 m
Now we calculate speed
v = x/t = 252.58/ 4.1 = 61.6 m/s
Finally
acceleration = v/t = 61.6/4.1 = 15 m/s²
Answer:
155.38424 K
2.2721 kg/m³
Explanation:
= Reservoir pressure = 10 atm
= Reservoir temperature = 300 K
= Exit pressure = 1 atm
= Exit temperature
= Specific gas constant = 287 J/kgK
= Specific heat ratio = 1.4 for air
Assuming isentropic flow

Flow temperature at exit is 155.38424 K
Density at exit can be derived using the ideal gas equation

Flow density at exit measures 2.2721 kg/m³
<span>A centripetal force maintains an object's circular motion. When the ball is at the highest point, we can assume that the ball's speed v is such that the weight of the ball matches the required centripetal force to keep it moving in a circle. Hence, the string will not become slack.
centripetal force = weight of the ball
m v^2 / r = m g
v^2 / r = g
v^2 = g r
v = sqrt { g r }
v = sqrt { (9.80~m/s^2) (0.7 m) }
v = 2.62 m/s
Thus, the minimum speed for the ball at the top position is 2.62 m/s.</span>
Response:
45cm
Clarification:
A converging mirror is generally termed a concave mirror. The focal length and the image distance for a concave mirror are both expressed as positive values.
Using the mirror formula to derive the object distance;

Where f denotes the focal length, u indicates the object distance, and v represents the image distance.
Given f = 30cm, and v = 2u (The formed image is double the size of the pencil)
Plugging these values into the formula to solve for u yields;

By cross-multiplying, we obtain;
2u = 90
Dividing both sides by 2;
2u/2 = 90/2
u = 45cm
The object's distance from the mirror measures 45cm