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olga55
9 days ago
8

Consider a very long, slender rod. One end of the rod is attached to a base surface maintained at Tb, while the surface of the r

od is exposed to an air temperature of 400°C. Thermocouples imbedded in the rod at locations 25 mm and 120 mm from the base surface register temperatures of 335°C and 375°C, respectively.
(a) Calculate the rod base temperature (°C).
(b) Determine the rod length (mm) for the case where the ratio of the heat transfer from a finite length fin to the heat transfer from a very long fin under the same conditions is 99 percent.

Engineering
1 answer:
mote1985 [204]9 days ago
3 0

Response:

(a) Compute the temperature at the base of the rod (°C). = 299.86°C

(b) Find the rod's length (mm) when the ratio of heat transfer from a finite length fin to that of a very long fin, under equivalent circumstances, is 99 percent.  = 0.4325m

Clarification:

refer to the file attached below

You might be interested in
At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g
mote1985 [204]

Response:

1) g=31.87ft/s^2

2)m=120

W=119.64lbf

Clarification:

initial segment

the weight of an object with a specified mass is determined using the equation

W=mg

we need to convert 120lb into slug

m=120lbx1slug/32.147lb=3.733slug

calculating for g

g=W/m

g=119/3.733=31.87ft/s^2

subsequent segment

the mass remains unchanged

m=120lb=3.733slug

Weight

W=3.733slug*32.05ft/s^2=119.64lbf

4 0
11 days ago
Write multiple if statements. If car_year is 1969 or earlier, print "Few safety features." If 1970 or later, print "Probably has
alex41 [274]

Answer:

The following includes the explanation, code, and resulting outputs.

C++ Code:

#include <iostream>

using namespace std;

int main()

{

int year;

cout<<"Enter the car model year."<<endl;

cin>>year;

if (year<=1969)

{

cout<<"Few safety features."<<endl;

}

else if (year>=1970 && year<1989)

{

cout<<"Probably has seat belts."<<endl;

}

else if (year>=1990 && year<1999)

{

cout<<"Probably has antilock brakes."<<endl;

}

else if (year>=2000)

{

cout<<"Probably has airbags."<<endl;

}

return 0;

}

Explanation:

The challenge involved displaying feature messages for a car based on its model year.

Logical conditions were integrated into the coding. The implementation has been verified with multiple inputs producing the expected results.

Output:

Enter the car model year.

1961

Few safety features.

Enter the car model year.

1975

Probably has seat belts.

Enter the car model year.

1994

Probably has antilock brakes.

Enter the car model year.

2005

Probably has airbags.

5 0
25 days ago
6. You are evaluating flow through an airway. The current flow rate is 10 liters per minute with a fixed driving pressure (P1) o
iogann1982 [279]

Answer:

B) P1 would have to increase to sustain the flow rate (correct)

C) Resistance would rise (correct)

Explanation:

Flow rate is measured at 10 liters per minute

Driving pressure (P1) stands at 20 cm H2O

Fixed downstream pressure (P2) is 5 cm H2O

The accurate statements when the lumen is pinched in the center of the tube are: P1 will increase to maintain the flow rate, and resistance will rise. This occurs because pinching the lumen decreases its diameter, leading to higher resistance, which is linearly related to pressure, thus P1 will also increase.

The incorrect statement is: the flow would decrease.

6 0
16 days ago
1. You do not need to remove the lead weights inside tires before recycling them.
Kisachek [217]
That's correct -.-.-.-.-.-.-.-.-.-.-.-.-.- Easy.
7 0
1 month ago
An AM radio transmitter operating at 3.9 MHz is modulated by frequencies up to 4 kHz. What are the maximum upper and lower side
Mrrafil [253]

Answer:

Total bandwidth: 8 kHz

Explanation:

Data provided:

Transmitter frequency: 3.9 MHz

Modulation up to: 4 kHz

Solution:

For the upper side frequencies:

Upper side frequencies = 3.9 × 10^{6} + 4 × 10³

Upper side frequencies = 3.904 MHz

For the lower side frequencies:

Lower side frequencies = 3.9 × 10^{6} - 4 × 10³

Lower side frequencies = 3.896 MHz

Consequently, the total bandwidth is computed as:

Total bandwidth = upper side frequencies - lower side frequencies

Total bandwidth = 8 kHz

6 0
19 days ago
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