The provided values are
$85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155
To start, we will arrange these in ascending order
resulting in
$60 $85 $95 $105 $120 $145 $155 $175 $190 $215 $235 $240 $260 $285 $315
The total count is 15
the position of 105 is 4
Now, we can calculate the percentile
Thus, the percentile for the bid of $105 is 26.667%...........Response
Answer:
16 years
Step-by-step explanation:
Let x represent the count of years. The suburb population increases at a rate of 5000 annually, which can be formulated as:
320000 + 5000x
The city population decreases at a rate of 14000 per year, represented as:
624000 - 14000x
The point in time when both the suburb and city populations will match can be derived from:
320000 + 5000x = 624000 - 14000x
14000x + 5000x = 624000 - 320000
19000x = 304000
x = 304000 / 19000
x = 16
In 16 years, the populations of both the suburb and the city will be equivalent
It is understood that
One tens corresponds to the number -----------> 
thus
tens translates to
hence
the result is
Answer:
dV(t)/dt = kV(t)
Step-by-step explanation:
The annual change in the car's value, represented by dV(t)/dt, has a proportional relationship with V(t), the car's current value.
dV(t)/dt ∝ V(t)
dV(t)/dt = kV(t)
The initial score was 80, and there was a wrongfully deducted 5 points. This indicates that any result equating to 85 is the correct outcome.
80 + 5 = 85
80 - (-5) = 85
