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Natali
2 months ago
5

here are Xavier's bowling scores: 135, 140, 130, 190, 112, 200, 185, 172, 163, 151, 149 What is the mean?

Mathematics
1 answer:
PIT_PIT [12.4K]2 months ago
7 0

Answer:

The average

Detailed breakdown:

the average is 157

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Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
Leona [12618]

Answer: Initially, he had 27 sweets.

Step-by-step explanation: The most logical approach is to work backwards from what remained after the third day to the start of the first day.

On the third day, he consumed one-third of his sweets and was left with 8. If we let the total sweets on day three be denoted as a, then one-third of a equals what he ate and the two-thirds left equals 8, giving us:

8/a = 2/3

By cross-multiplying, we find:

8 x 3 = 2a

Therefore, 24 = 2a

This leads to a = 12.

Let the sweets on day two be represented as b. If he consumed one-third of b and was left with 12, we have the same structure; hence:

12/b = 2/3

Cross-multiplying gives:

12 x 3 = 2b

So, 36 = 2b, leading to b = 18.

Denote the number of sweets on day one as x. If one-third of x was eaten and 18 remained, we can set up the equation:

18/x = 2/3

Again, cross-multiplying results in:

18 x 3 = 2x

Which simplifies to 54 = 2x, yielding x = 27.

Thus, Tim received 27 sweets at the start.

3 0
3 months ago
A common inhabitant of human intestines is the bacterium Escherichia coli, named after the German pediatrician Theodor Escherich
babunello [11817]
A.) P(t) = P0e^(kt)
P(20/60) = 40 e^(20k/60)
80 = 40 e^(k/3)
e^(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)

b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells

d.) Rate of change = e^(8k) = e^(8(3ln(2))) = e^(24ln(2)) = e^(16.6355) = 16777216 cells/hour

e.) P(t) = 40(2)^(3t); t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours
8 0
2 months ago
Read 2 more answers
Archimedes (ca. 287-212 B.C.) was able to use clever geometric means to determine the relative volumes of a cylinder and the con
Zina [12379]

Answer:

The ratio comparing the volume of a cone to that of a cylinder is \frac{V_{cone}}{V_{cy}} = \frac{1}{3}

Step-by-step explanation:

According to the provided information

The formula for the volume of a cone is described as

V_{cone} = \frac{1}{3} \pi r^2 h

The expression for the volume of a cylinder can be given as

V_{cy} = \pi r^2 h

Thus, the ratio we seek to find is

\frac{V_{cone}}{V_{cy}} = \frac{\frac{1}{3} \pi r^2 h}{\pi r^2 h}

\frac{V_{cone}}{V_{cy}} = \frac{\frac{1}{3} }{1} This is achievable since both the height and base

\frac{V_{cone}}{V_{cy}} = \frac{1}{3} radius remain identical

6 0
1 month ago
A CAT scan produces equally spaced cross-sectional views of a human organ that provide information about the organ otherwise obt
zzz [12365]
1,107 cc The scanning consists of 10 intervals: [0,1.5), [1.5,3), [3,4.5), [4.5,6), [6,7.5), [7.5,9), [9,10.5), [10.5,12), [12,13.5), [13.5,15) To estimate the volume using the Midpoint Rule, n should be set to 10. Given that we will use n=5, we will split the range [0,15] into five intervals of lengths 3 each: [0,3], [3,6], [6,9], [9,12], [12,15] and calculate their midpoints: 1.5, 4.5, 7.5, 10.5, and 13.5. Next, we will determine the volume V from the five cylinders, where each has a height h=3 and the base area A corresponds to the calculated midpoints' intervals: Cylinder 1 Midpoint=1.5, corresponding to the 2nd interval A = 18, V= height * area of the base = 18*3 = 54 cc Cylinder 2 Midpoint=4.5, corresponding to the 4th interval A = 78, V= height * area of the base = 78*3 = 234 cc Cylinder 3 Midpoint=7.5, corresponding to the 6th interval A = 106, V= height * area of the base = 106*3 = 318 cc Cylinder 4 Midpoint=10.5, corresponding to the 8th interval A = 129, V= height * area of the base = 129*3 = 387 cc Cylinder 5 Midpoint=13.5, corresponding to the 10th interval A = 38, V= height * area of the base = 38*3 = 114 cc Thus, the estimated volume is 54 + 234 + 318 + 387 + 114 = 1,107
6 0
2 months ago
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