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Degger
2 months ago
6

Suppose you perform a calorimeter experiment to determine the molar heat of neutralization of an unknown acid, H A HA, with sodi

um hydroxide, N a O H NaOH. You mix 37.2 mL of 0.50 M H A HA with 56.8 mL of 0.75 M N a O H NaOH and calculate the heat of reaction as -1.6 kJ. What is the molar heat of neutralization (in kJ/mol) for the unknown acid
Chemistry
1 answer:
Alekssandra [3K]2 months ago
5 0

Answer:

-86.02 kJ/ mole

Explanation:

The amount of acid utilized in moles = Molarity × Volume (L) =

= 0.50 (0.0372 L)

= 0.0186 moles

The energy released = -1.6 kJ

Thus, 0.0186 moles of HA neutralization results in: -1.6 kJ

The molar heat of neutralization for one mole of the unidentified acid is = -1.6/0.0186

= -86.02 kJ/ mole

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