Answer: 36.53g
Explanation:
To determine the mass of NaCl that dissolves in 1L of solution yielding 5M of NaCl:
Molarity = 5M
Molecular mass (MM) of NaCl = 58.45
Molarity = Mass concentration (g/L) / MM
Mass concentration (g/L) of NaCl = Molarity × MM
= 5 × 58.45 = 292.25g
Now, for 125mL (0.125L), the amount dissolving is determined:
292.25g of NaCl is found in 1L of solution;
Thus, Xg of NaCl dissolves in 0.125L, which is:
Xg of NaCl = 292.25 × 0.125 = 36.53g.
Hence, 36.53g of NaCl dissolves in 125mL of solution.
