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Deffense
8 days ago
7

How many grams of solute are dissolved in 125.0 mL of 5.00 M NaCl (MM = 58.45)?

Chemistry
1 answer:
lorasvet [956]8 days ago
5 0

Answer: 36.53g

Explanation:

To determine the mass of NaCl that dissolves in 1L of solution yielding 5M of NaCl:

Molarity = 5M

Molecular mass (MM) of NaCl = 58.45

Molarity = Mass concentration (g/L) / MM

Mass concentration (g/L) of NaCl = Molarity × MM

= 5 × 58.45 = 292.25g

Now, for 125mL (0.125L), the amount dissolving is determined:

292.25g of NaCl is found in 1L of solution;

Thus, Xg of NaCl dissolves in 0.125L, which is:

Xg of NaCl = 292.25 × 0.125 = 36.53g.

Hence, 36.53g of NaCl dissolves in 125mL of solution.

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The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which
Alekssandra [968]

Answer:

25.2 kJ

Explanation:

The full question can be found in the image linked to this response.

It's important to highlight that the heat absorbed by the 2.00 L of water for increasing its temperature from the beginning to the end comes solely from the burning of benzoic acid, as there are no heat transfers to the container or the surroundings.

To find the heat released from benzoic acid combustion, we simply measure the heat needed to warm the water.

Q = mCΔT

To find the mass of the water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

C = specific heat of water = 4.2 J/g.°C

ΔT = (final temperature) - (Initial temperature)

<pAccording to the graph,

Final water temperature = 25°C

Initial water temperature = 22°C

ΔT = 25 - 22 = 3°C

Q = (2000×4.2×3) = 25,200 J = 25.2 kJ

Hope this Helps!!!

6 0
8 days ago
The atomic radius of magnesium is 150 pm. The atomic radius of strontium is 200 pm. What is the atomic radius of calcium
castortr0y [923]

Answer:

Calcium's atomic radius is roughly 175 pm.

Explanation:

We know that magnesium has an atomic radius of 150 pm.

The atomic radius of strontium measures 200 pm.

Since calcium's position is between magnesium and strontium in group 2 of the periodic table, its atomic radius should be roughly averaged between magnesium's and strontium's atomic radii because atomic radius is not constant.

Thus;

Calcium's atomic radius is approximately calculated as follows;

The average atomic radius is (200 + 150)/2 = 175 pm.

7 0
12 days ago
65g of nitric acid are produced in a reaction. 2.5g of platinum are added to the reaction vessel at the start of the reaction to
alisha [964]

Answer:

2.5 g of platinum

Explanation:

A catalyst is a substance added to a reaction to enhance the reaction speed. It does not undergo any change during the reaction, meaning it remains unchanged after the reaction concludes. The role of a catalyst is to provide an alternative pathway for the reaction by reducing the activation energy required. Therefore, a catalyzed reaction occurs more rapidly and requires less energy compared to an uncatalyzed one.

Since catalysts do not get involved in reactions and retain their mass post-reaction, the amount of platinum will stay the same (2.5g). The mass can only alter if a substance participates in the chemical process. Thus, this is the response.

6 0
3 days ago
Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S
Anarel [852]

Explanation:

Elements provided:

  F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements sharing similar reactivity belong to the same group in the periodic table, indicating that those in the same column exhibit comparable reactivity. Here are the identified groupings:

  Li and Rb are alkali metals in group 1

  Ca and Sr are alkaline earth metals in group 2

  F and Br are halogens in group 7

  O and S belong to group 6

 P and Sb are classified in group 5 of the periodic table

Thus, these classifications illustrate elements with the same chemical characteristics.

7 0
11 days ago
When drawing the Lewis structure for a molecule, after drawing the skeletal structure and distributing all of the electrons arou
Anarel [852]

Answer: Rearrange the lone pairs of electrons from the outer atom(s) to create double or triple bonds with the central atom.

Explanation:

7 0
2 days ago
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