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bulgar
2 months ago
9

The equation r = 6t gives the number of albums released, r, by a record label over time in years, t. If you graph this relations

hip with time along the x-axis and the number of albums along the y-axis, which points lie on the resulting line?
Mathematics
2 answers:
tester [12.3K]2 months ago
7 0

Response:

The correct choices are:

b & e

I completed the test and got it right!

Hope this was useful:3

PIT_PIT [12.4K]2 months ago
4 0
Options:
(7, 44)
(8, 48)
(9, 52)
(12, 74)
<span>(13, 78)

r = 6t 
(7,44): r = 6(7) = 42 is incorrect 
(8,48): r = 6(8) = 48 is the CORRECT answer
(9,52): r = 6(9) = 54 is incorrect
(12,74): r = 6(12) = 72 is incorrect
(13,78): r = 6(13) = 78 is the CORRECT answer

The coordinates on the line produced are (8,48) and (13,78)</span>
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Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number
tester [12383]

Answer:Part a) 2,50,18

Part b) When Jenny divides the square root of her favorite positive integer by \sqrt{2}, the result is an integer.

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For x=2

\sqrt{2}*\sqrt{2}=\sqrt{4}=2 -----> the product results in an integer

thus

The number x=2could potentially be Jenny's favorite positive integer

2) For x=50

\sqrt{50}*\sqrt{2}=\sqrt{100}=10 -----> the product results in an integer

thus

The number x=50could potentially be Jenny's favorite positive integer

3) For x=18

\sqrt{18}*\sqrt{2}=\sqrt{36}=6 -----> the product results in an integer

thus

The number x=18could potentially be Jenny's favorite positive integer

Part B)

1) For x=2

\sqrt{2}/\sqrt{2}=\sqrt{1}=1 -----> the outcome is an integer

2) For x=50

\sqrt{50}/\sqrt{2}=\sqrt{25}=5 -----> the outcome is an integer

3) For x=18

\sqrt{18}/\sqrt{2}=\sqrt{9}=3 -----> the outcome is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by \sqrt{2}, she obtains an integer as a result.

4 0
1 month ago
Tickets to a play are $12.00 for adults. Children receive a discount and only have to pay $8.00. If 40 people attend the play an
AnnZ [12381]
There were 30 adults and 10 children, totaling 40 attendees. Just sum them together.
3 0
2 months ago
A square lot has sides of 39.875 m<br> Which is the best estimate for the perimeter of the lot?
PIT_PIT [12445]
b
4 0
1 month ago
Ann and Bill play rock-paper-scissors. Each has a strategy of choosing uniformly at random out of the three possibilities every
Inessa [12570]

Answer:

a) Ann has a 1/3 chance of winning in the first round

b) The chance of Ann winning for the first time in the fourth round is 8/81

c) The probability that Ann's first win occurs after the fourth round is 16/81

Step-by-step explanation:

a) Each strategy is played with a probability of 1/3. Given any strategy, there’s a 1/3 chance that Bill will choose the strategy that allows Ann to win. Consequently, the probability of Ann securing a victory in the first round (or any round) is

1/3 * 1/3 + 1/3 * 1/3 + 1/3 * 1/3 = 1/9 + 1/9 + 1/9 = 1/3.

Thus, the likelihood of Ann winning the initial round is 1/3.

b) The chances of Ann winning a round stand at 1/3; therefore, her chances of not winning are 2/3. This must happen three times before her first victory. Thus, the probability that Ann's first win occurs in the fourth round is

(2/3)³ * 1/3 = 8/81.

c) The first victory happens after the fourth round if she remains unsuccessful in the first four rounds, translating to a possibility of (2/3)⁴ = 16/81.

8 0
2 months ago
1. X^4(dy/dx) +x^3y =- sec (xy)<br><br>Integral by separation of variables? <br>​
PIT_PIT [12445]

Answer:

Step-by-step explanation:

Considering the differential equation x^4(dy/dx) + x^3y = -sec(xy). We will solve it employing the method of separation of variables;

x^{4} \frac{dy}{dx} +x^{3}y = -sec(xy)\\x^{3}(x\frac{dy}{dx} + y) = -sec(xy)\\let \ v=xy\\\frac{dv}{dx} = x\frac{dy}{dx} + y(implicit \ in\ nature)\\

By substituting v and dv/dx into the previous equation, we acquire;

x^{3}\frac{dv}{dx} = -secv

We then separate the variables:

-\frac{dv}{secv} = \frac{dx}{x^{3} }

-cosvdv = x^{-3}dx\\ integrating\ both\ sides\\-\int\limits {cosv} \, dv = \int\limits {x^{-3} } \, dx\\-sinv = \frac{x^{-2} }{-2} + C\\since\ v = xy\\-sinxy = \frac{x^{-2} }{-2} + C\\2sin(xy) = x^{-2} -2C\\2 sin(xy) = \frac{1}{x^{2} } -K (where\ K = 2C)\\

The end expression provides the solution to the differential equation.

8 0
2 months ago
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