A basement bedroom must have a window with an opening area of at least 5.7 square feet, per the International Residential Code.

Answer:

Part A: During the interval from 0 to 2 seconds, the water balloon reaches a height of 75 feet from an initial height of 60 feet, showing an increase in height during [0,2]

Part B: Between 2 to 4 seconds, the height remains constant at 75 feet, indicating a stable height during [2,4]. Similarly, from 10 to 12 seconds, the height stays at 0 feet, thus remaining unchanged during [10,12] and from 12 to 14 seconds, it also remains at 0 feet, indicating stability during [12,14].

Part C: The water balloon height decreases most rapidly between the intervals [4,6], dropping by 35 feet. The other intervals that show a decrease, [6,8] and [8,10], drop by 20 feet each. Thus, it reveals that the decreasing interval [4,6] is the most significant, as 35 feet is a more considerable reduction compared to 20 feet.

Part D: I estimate that at 16 seconds, the height of the water balloon will be 0 feet. This correlates with the height of the balloon being 0 feet between 10 and 14 seconds. In real-life contexts, if the balloon rests on the ground at 0 feet, it stays on the ground because of gravitational force.

Step-by-step explanation:

I hope this offers some assistance! I can't confirm if everything is accurate, but I have researched thoroughly, so fingers crossed it is correct! Best of luck!

Response:

$14

Step-by-step explanation:

35 divided by 20 equals 1.75

8 multiplied by 1.75 results in 14

Response:

Detailed explanation:

The length of the pool is longer than its width by 8 meters.

If we designate L as length and W as width, we can express this as:

L = 8 + W

We also know that the area amounts to 105 m squared.

Note:

Area of a Rectangle = Length x Width

Thus, 105 = (8 + W) x W

To adjust the equation, subtract 105 from both sides:

Given:

It is stated that

PQ ⊥ PS and

∠QPR = 7x-9

∠RPS = 4x+22

To find the measure of ∠QPR.

Formula

According to the problem PR sits between PQ and PS,

Consequently,

∠QPR+∠RPS = 90°

Now,

Inserting the values for ∠RPS and ∠QPR yields

or,

or,

or,

or,

Substituting the value of into ∠QPR gives us

∠QPR =

or, ∠QPR =

So,

The measure of ∠QPR is 40°.