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1 month ago

Liam throws a water balloon horizontally at 8.2 m/s out of a window 18 m from the ground.

Physics

1 answer:

Yuliya22 [3.3K]1 month ago

5 0

The time required for the water balloon to reach the ground is given as

$h = \frac{1}{2} gt^2$

Here we understand that

$h = 18 m$

$g = 9.8 m/s^2$

Now applying the earlier mentioned formula

$18 = \frac{1}{2}*9.8* t^2$

$18 = 4.9 t^2$

$t = 1.92 s$

Now in the same time frame, we can conclude the distance covered will be

$d = v_x * t$

$d = 8.2 * 1.92 = 15.7 m$

Thus, it will land at a distance of 15.7 m from where it started

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Hence, we can conclude that:

$\Delta t_{o} = \Delta t$

where

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