Answer:
1. The force applied by the shelf supporting the book.
Explanation:
The free body diagram for the book is represented as follows:
1 - The weight of the book acting downward
2 - The normal force exerted by the shelf upward on the book.
As the book remains stationary, these two forces balance each other, and in accordance with Newton's Third Law, the reactive force equivalent to gravity is opposite and equal to the weight of the book. This reaction force prevents the book from falling off the shelf.
Even if we lack details about the size of the pressure cooker or the altitude of its operation, we can reliably assess the force on the lid based on prior knowledge because, similar to boiling water, the pressure buildup inside the cooker increases in line with the rising temperature.
275 kPa Explanation: Here the mass of the gas equals m=1.5 kg with an initial volume of V₁=0.04 m³ and an initial pressure P₁=550 kPa. As provided, the final volume is double the original volume, making V₂ equal to 2 V₁. Since the temperature remains constant, T₁=T₂=T. By substituting the values into the equation... results in final pressure being P₂=275 kPa.
Answer and Explanation:
currents i = 2.9 A
i ' = 4.4 A
The magnitude (in T.m) of the path integral of B.dl around the window frame is calculated as = μo * the enclosed current
= μo* ( i ' - i )
According to Ampere's law
where μo = permeability of free space = 4π * 10 ^-7 H/m
Substituting the values gives us the magnitude (in T.m) of the path integral of B.dl = (4π*10^-7)(2.9+4.4)
= 1.884 * 10^-6 Tm
