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QveST
7 days ago
5

Liam throws a water balloon horizontally at 8.2 m/s out of a window 18 m from the ground.

Physics
1 answer:
Yuliya22 [2.4K]7 days ago
5 0

The time required for the water balloon to reach the ground is given as

h = \frac{1}{2} gt^2

Here we understand that

h = 18 m

g = 9.8 m/s^2

Now applying the earlier mentioned formula

18 = \frac{1}{2}*9.8* t^2

18 = 4.9 t^2

t = 1.92 s

Now in the same time frame, we can conclude the distance covered will be

d = v_x * t

d = 8.2 * 1.92 = 15.7 m

Thus, it will land at a distance of 15.7 m from where it started

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