Answer:
17.35 × 10^(-6) m
Explanation:
Mass; m = 50 kg
Weight; W = 554 N
From the formula:
W = mg
This simplifies to; 554 = 50g
g = 554/50
g = 11.08 m/s²
Also, using the formula;
mg = GMm/r²
hence; g = GM/r²
Rearranging gives;
r = √(GM/g)
With G as a known constant of 6.67 × 10^(-11) Nm²/kg²
r = √(6.67 × 10^(-11) × 50/11.08)
r = 17.35 × 10^(-6) m
Answer:
The air exiting from the hairdryer is moving at a speed of 10 m/s.
Explanation:
The thrust generated by the hairdryer enables it to maintain an elevation angled at 5° from vertical; thus, we derive from the force diagram

by substituting
,
into the equation and resolving for
we find:



This thrust is linked to the speed of air ejection
through the equation

where
signifies the rate of air ejection, which is known to be

and since
,


by inserting these values into equation (2), we obtain the value of
as:

resulting in


which indicates the air velocity discharged from the hairdryer.