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aleksley
2 months ago
9

Researchers stationed at different areas on a mountain and in a tunnel midway through the mountain boiled water at the same time

. Even though the water at every station was at the same temperature, the pot at the top of the mountain started boiling before the others. Why?
Water boils when the vapor pressure is___________ the atmospheric pressure. The atmospheric pressure_________ at the top of the mountain.


choices for blank 1: less than ---greater than----equal to
choices for blank 2: is greatest---is least---equals to standard pressure
Chemistry
1 answer:
VMariaS [2.9K]2 months ago
6 0

Moving on to the second issue

Let's tackle the second question first. Once you grasp that, the first question will be simpler. By the way, this is an excellent question to clarify. The concepts of less than and more than can be quite tricky in the sciences. Every question you encounter that utilizes less or more should be approached with caution.

As altitude increases, air pressure decreases (essential term: less highlight this sentence in color. Take a moment to reflect on it.)

As the pressure declines, less energy (again, key term) is required for water molecules to escape the surface. Thus, the boiling temperature is lower than it would be at sea level.

Answer to problem two: Lower

Problem One

Water reaches its boiling point when the greatest number of molecules can leave the water's surface. Equal to is the right answer.  Although pinpointing the exact answer can be challenging, equal to is indeed the correct response.

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Approximately 220 million tires are discarded in the U.S. each year. These tires present a disposal problem because they take up
lions [2927]

Answer:

A total of 2667 tires are required to satisfy the annual power needs of ten homes.

Explanation:

According to the Second Law of Thermodynamics, not all energy produced when tires are incinerated can be effectively used due to losses associated with finite temperature differences. The energy obtainable from a tire when burned, measured in kilowatt-hours (E_{out}), can be calculated using the efficiency definition:

E_{out} = \eta \cdot E_{in}

Where:

\eta - Efficiency, which is dimensionless.

E_{in} - Energy released from burning, measured in kilowatt-hours.

Taking into account \eta = 0.5 and E_{in} = 75\,kWh, the yearly energy yield from a tire amounts to:

E_{out} = 0.5\cdot (75\,kWh)

E_{out} = 37.5\,kWh

Thus, the number of tires necessary to meet the electricity demand of ten homes for one year is:

n = \frac{(10\,homes)\cdot \left(10000\,\frac{kWh}{home} \right)}{37.5\,\frac{kWh}{tire} }

n = 2666.667\,tires

A total of 2667 tires are necessary to satisfy the annual power needs of ten homes.

8 0
2 months ago
How many moles of chromium metal equal 7.52 × 1022 atoms Cr?
Alekssandra [3086]

Response:

0.125 moles

Explanation:

According to Avogadro's principle, one mole of any substance contains 6.02x10^23 atoms.

This implies that 1 mole of chromium consists of 6.02x10^23 atoms.

Therefore, if 1 mole of chromium corresponds to 6.02x10^23 atoms,

Then X moles of chromium are equivalent to 7.52x10^22 atoms, thus

X moles of chromium = 7.52x10^22/6.02x10^23

Thus, X moles of chromium = 0.125 moles

Consequently, 0.125 moles of chromium contain 7.52x10^22 atoms

8 0
1 month ago
Sea water's density can be calculated as a function of the compressibility, B, where p = po exp[(p - Patm)/B]. Calculate the pre
lions [2927]

Answer:

A pressure of 137.14 MPa exists 10,000 m beneath the ocean surface.

At this same depth, the density measures 2039 kg/m3.

Explanation:

P0 and ρ0 symbolize the pressure and density at sea level (indicative of atmospheric conditions). With an increase in ocean depth, both pressure and density likewise rise.

The relationship between pressure and density can be expressed as:

\frac{dP}{dy}=\rho*g=\rho_0*g*e^{(P-P_0)/\beta\\\\

By rearranging

\frac{dP}{e^{(P-P_0)/\beta}}= \rho_0*g*dy\\\\\int\limits^{P}_{P_0} {e^{-(P-P_0)/\beta}}dP =\int\limits^y_0 {\rho_0*g*dy}\\\\(-\beta*e^{-(P-P_0)/\beta})-(\beta*e^0)=\rho_0*g*(y-0)\\\\-\beta*(e^{-(P-P_0)/\beta}-1)=\rho_0*g*y\\\\e^{-(P-P_0)/\beta}=1-\frac{\rho_0*g*y}{\beta}\\\\-\frac{P-P_0}{\beta} =ln(1-\frac{\rho_0*g*y}{\beta})\\\\P-P_0=-\beta*ln(1-\frac{\rho_0*g*y}{\beta})\\

This equation allows for computation of P at 10,000 m beneath the ocean's surface:

P-P_0=-\beta*ln(1-\frac{\rho_0*g*y}{\beta})\\\\P-P_0=-200MPa*ln(1-\frac{1027kg/m^3*9.81m/s^2*10,000m}{200MPa})\\\\P-P_0=-200MPa*ln(1-\frac{1027*9.81*10,000Pa}{200*10^6Pa})\\\\P-P_0=-200MPa*ln(1-0.5037)\\\\P-P_0=-200MPa*(-0.6857)=137.14MPa

The density found at a depth of 10,000 m in the ocean is

\rho=\rho_0*e^{(P-P_0)/\beta}\\\rho=1027kg/m^3*e^{(137.14/200)}=1027*e^{0.686}kg/m^3\\\rho=1027*1.985 kg/m^3\\\rho=2039\,kg/m^3

4 0
2 months ago
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