Answer:
0.0181 mol H
Explanation:
Step 1: Provided data
Moles of water (H₂O) produced during the process: 0.00905 mol H₂O
Step 2: Determine the quantity of H (in mol) present in 0.00905 mol of H₂O
According to the H2O chemical formula, the ratio of water to hydrogen is 1:2, meaning 2 moles of H exist for every mole of H₂O. This conversion factor will be applied to find the moles of H contained in 0.00905 moles of H₂O.
0.00905 mol H₂O × (2 mol H/1 mol H₂O) = 0.0181 mol H
Answer:
The proportion of the family's overall yearly electricity that is attributed to running both air conditioners over the summer months is = 19.4 %
Explanation:
Monthly average electricity usage = 900 kWh
The family utilizes two window air conditioners to cool their residence during summer for three months.
The electricity usage for a single window-unit air conditioner = 350 kWh
The total power utilized by both window-unit air conditioners = 350(2) = 700 kWh
The total power consumed by two air conditioners for the summer months = 700 (3) = 2100 kWh
The annual total power consumption = 900 (12) = 10800 kWh
The percentage of the family's total annual electricity for operating the air conditioners during summer =
= 19.4 %
Answer:
B.
Explanation:
Elemental analysis reveals the precise percentage make-up of each component in the compound sample. Here, we have two distinct compounds, both containing copper and oxygen. However, the specific amounts of copper and oxygen in these compounds remain unknown.
An elemental composition will clarify this aspect and aid in determining the chemical formula for each compound, since the percentage of each element is now understood.
ΔH = 3KJ. La chaleur totale absorbée représente l'énergie totale du processus, et cela se mesure en termes d'enthalpie. ΔH = q + ΔHvap, où q représente la chaleur nécessaire pour élever la température du diéthyl-éther. Supposons que la température initiale soit ambiante (25ºC = 298 K), alors q = 10g x 2.261 J/gK x (310 K - 298 K) = 271,32 J = 0,3 kJ. Ensuite, ΔHvap = 10g C4H10O x (1 mol C4H10O / 74,12 g C4H10O) x (15,7 KJ / 1 mol C4H10O) = 2,12 KJ. Ainsi, ΔH = 2,5 KJ ≈ 3 KJ.
Always ensure that the equation is balanced initially. (This question's equation is already balanced) 6.022 x 10^23 refers to Avogadro’s number. In one mole of any substance, there are invariably 6.022 x 10^23 molecules, formula units, or atoms. For a single mole of any element or compound, you should use the molar mass (grams).
Calculate the product of the values on the top = 8.61x10^47
Calculate the product of the values on the bottom = 1.20x10^24
Divide the results of the top by the bottom = 7.15x10^23
Final result: 7.15x10^23 mol SO2