What precisely is being followed here?
The enthalpy change associated with the precipitation reaction is 84 kJ/mole
Why?
The chemical equation for the reaction can be written as
AgNO₃(aq) + NaCl (aq) → AgCl(s) + NaNO₃(aq)
To determine the enthalpy change, the following equation applies

To calculate the heat (Q):

Next, we need to calculate the number of moles involved in the reaction (n):
![n=[AgNO_3]*v(L)=(0.1M)*(0.05L)=0.005moles](https://tex.z-dn.net/?f=n%3D%5BAgNO_3%5D%2Av%28L%29%3D%280.1M%29%2A%280.05L%29%3D0.005moles)
With these two values, we can substitute them into the first equation:

Have a great day!
Answer:
[Cl⁻] = 0.016M
Explanation:
To begin, we analyze the reaction:
Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓ + Mg(NO₃)₂(aq)
This indicates a solubility equilibrium, resulting in the formation of lead(II) chloride precipitate. The salt can dissociate as follows:
PbCl₂(s) ⇄ Pb²⁺ (aq) + 2Cl⁻ (aq) Kps
Initial x
React s
Eq x - s s 2s
Given that this is an equilibrium scenario, the Kps serves as the constant (Solubility product):
Kps = s. (2s)²
Kps = 4s³ = 1.7ₓ10⁻⁵
4s³ = 1.7ₓ10⁻⁵
s = ∛(1.7ₓ10⁻⁵. 1/4)
s = 0.016 M
Atoms have their protons and neutrons situated in the nucleus.
Electrons orbit in the outer shells, also known as orbitals.
Subatomic particles, comprising protons, neutrons, and electrons, reside within the atoms.
Answer:
Explanation:
The concept of mass balance around a distillation tower is utilized.
Each column undergoes mass and component balance, with relevant substitutions and analyses detailed in the attached documents.