Answer:
3.816 × 10⁻³ M
Explanation:
A stock solution of Cu²⁺(aq) is made by dissolving 0.8875 g of solid Cu(NO₃)₂∙2.5H₂O in a 100.0-mL volumetric flask, and then brought up to volume with water. What is the molarity (in M) of Cu²⁺(aq) in this stock solution?
We can derive the following relations:
- The molar mass of Cu(NO₃)₂∙2.5H₂O is 232.59 g/mol.
- Each mole of Cu(NO₃)₂∙2.5H₂O yields one mole of Cu²⁺.
The moles of Cu²⁺ present in 0.8875 g of Cu(NO₃)₂∙2.5H₂O are:
The molarity of Cu²⁺ is:
Answer:
0.605 molal
Explanation:
Molality indicates the solute amount in a specific solvent mass.
Let’s find the amount of benzene solute.
Mass of benzene = 13.3g
Molar mass of C6H6 = 12*6 +1*6 =72+7=78g/mol
Amount of benzene = mass/molar mass
=13.3/78
=0.1705mol
Molality = amount of solute/mass of solvent in kg
Mass of solvent = 282g = 0.282kg
Molality = 0.1705/0.282
=0.605 molal
Answer:
Oversight of weights and measures ensures correct evaluations of goods and services so that everyone receives a fair exchange in the marketplace. It also acts as a deterrent, promoting honesty among traders.
Explanation:
Answer:
The correct answer is "Speed".
Explanation:
- An intensive or individualized physical property is identified when "speed" is observed as the excretion of an individual in a confined area, capable of reaching someone one meter away after sneezing or coughing.
- This measure is represented in the unit of "meter per second", indicating its intensive nature.
In the container with a volume of 1 L, the total amount of gas is 0.0446 moles, whereas in a 3 L container, it is 0.1334 moles. Explanation: Since 1 mole of gas occupies 22.4 liters, to find the total gas quantity present in both the 1 L and 3 L containers, we divide the respective volumes by the reciprocal of 22.4 liters, leading to the determination of the moles of gas at each volume. Hence for 1 L, there are 0.0446 moles, and for 3 L, it is calculated to be 0.1334 moles. Thus, it can concluded that the number of moles increases with a rise in volume or expansion of gas.
