Response:1816.6 joules
Clarification:refer to the attached image
Hello, in this situation, the chemical reaction occurring is as follows: Next, we will ascertain the limiting reactant by calculating the moles of magnesium oxide produced from 3.86 g of magnesium and 155 mL of oxygen using the given mole ratios of 2:1:2 and applying the ideal gas equation, demonstrating that oxygen is the limiting reactant because it generates the least magnesium oxide. Subsequently, we determine the mass of magnesium consumed solely by the oxygen.
Answer: Option (a) is the correct answer.
Explanation:
Under conditions of low pressure and high temperature, gas molecules exhibit negligible attractions or repulsions among themselves. Hence, gases behave ideally in these scenarios.
Conversely, at low temperatures, there is a reduction in the kinetic energy of gas molecules, while high pressure compels the molecules to be closer together.
Thus, attractive forces emerge between molecules in conditions of low temperature and high pressure, causing gases to be termed real gases.
Therefore, we conclude that the ideal gas law becomes less accurate when pressure increases and temperature decreases.
Answer:
The molality is 1.15 m.
Molality is calculated by dividing the number of moles of solute by the kilograms of solvent, which in this case is water.
Calculate moles of H₂SO₄ from molarity:
C = n/V → n = C × V = 6.00 mol/L × 0.048 L = 0.288 moles
Mass of solvent (water) based on density:
m = ρ × V = 1.00 kg/L × 0.250 L = 0.250 kg
Therefore, molality is:
m = moles/solvent mass = 0.288 moles / 0.250 kg = 1.15 m