When listening to tuning forks of frequency 256 Hz and 260 Hz, one hears the following number of beats per second. (A) 0 (B) 2 (
1 answer:
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Answer:
The system's energy amounts to 15 J.
Explanation:
Given that,
Energy E = 2.5 J
Amplitude = 10 cm
The spring constant needs to be computed.
Using the formula for the mechanical energy of the system,
Substituting the values into the formula:
If the block is swapped out for one with double the original mass,
Amplitude = 6 cm
We need to find the energy
Using the mechanical energy formula,
Substituting into the formula:
Thus, the system’s energy is 15 J.
Answer:
C = 4,174 10³ V / m^{3/4}, E = 7.19 10² / ∛x, E = 1.5 10³ N/C
Explanation:
In this problem, we are tasked with determining the constant value and the generated electric field.
We will begin with computing the constant C:
V = C
C = V / x^{4/3}
C = 220 / (11 10⁻²)^{4/3}
C = 4,174 10³ V / m^{3/4}
Next, we will find the electric field by utilizing the formula:
V = E dx
E = dx / V
E = ∫ dx / C x^{4/3}
E = 1 / C x^{-1/3} / (- 1/3)
E = 1 / C (-3 / x^{1/3})
We consider the evaluation from the lower limit x = 0 where E = E₀ = 0 to the upper limit x = x, resulting in E = E:
E = 3 / C (0- (-1 / x^{1/3}))
E = 3 / 4,174 10³ (1 / x^{1/3})
E = 7.19 10² / ∛x
Substituting x = 0.110 cm:
E = 7.19 10² /∛0.11
E = 1.5 10³ N/C