answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bogdan
2 months ago
11

A shoe manufacturer compared material A and material B for the soles of shoes. Twelve volunteers each got two shoes. The left wa

s made with material A and the right with material B. On both shoes, the material was 1 inch thick. Volunteers used the shoes normally for two months and returned them to the manufacturer. Technicians then measured the thickness of the soles and recorded the amount of wear (in microns):
Volunteer 1 2 3 4 5 6 7 8 9 10 11 12
Sole A 379 378 328 372 325 304 356 309 354 318 355 392
Sole B 372 376 328 368 283 252 369 321 379 303 328 411

They wish to test
H0: µA −µB = 0
against
HA: µA −µB 6= 0,

where µA and µB are the unknown population mean amounts of sole wear, using α = 0.05.

(a) Are the two samples paired or independent? Explain your answer.
(b) Make a normal QQ plot of the differences within each pair. Is it reasonable to assume a normal population of differences?
(c) Choose a test appropriate for the hypotheses above and justify your choice based on your answers to parts (a) and (b). Perform the test by computing a p-value, make a test decision, and state your conclusion in the context of the problem

Mathematics
1 answer:
AnnZ [12.3K]2 months ago
4 0
a) These samples are dependent, as measurements are taken from the same individuals at different times using different methods. b) Upon examining the QQ plot, it shows no considerable deviations suggesting a normal distribution assumption for the differences. c) For the hypotheses indicated, a paired t-test is suitable due to the repeated measurements. Evaluating the p-value reveals it exceeds the significance threshold, leading to the conclusion that we FAIL to reject the null hypothesis, thus indicating that the mean difference is not significantly different from 0.
You might be interested in
Three people toss a fair coin and the odd one pays for coffee. if the coins all turn up the same, they are tossed again. find th
lawyer [12517]

In the absence of a specific question posed, below are the potential inquiries along with their respective answers:

P(fewer than 4 tosses)
= P(one toss) + P(two tosses) + P(three tosses)
= (3/4) + (3/4)(1/4) + (3/4)(1/4)^2
= 0.984375


Expected value
= 1 / p
= 1 / (3/4)
= 4 / 3

Variance
= (1 - p) / p^2
= (1 - (3/4)) / (3/4)^2
= (1/4) / (9/16)
= 4 / 9

Standard deviation
= sqrt(Variance)
= sqrt(4 / 9)
= 2 / 3

8 0
2 months ago
Express the quantity of water flowing into a tank as a linear function of time. Then identify the quantity of water in the tank
babunello [11817]

what was the response

4 0
2 months ago
According to a survey by Bankrate, of adults in the United States save nothing for retirement (CNBC website). Suppose that adult
tester [12383]

Complete Question

The complete question appears in the first uploaded image

Answer:

a) Yes, selecting 15 corresponds to a binomial experiment

b)

c)

d) P(r = 15) = 3.2768 *10^{-11}

Step-by-step explanation:

Regarding question a:

For an experiment to qualify as binomial

the trials have to be independent

each trial must yield one of two possible outcomes

Given that the selection of 15 individuals is random, we ascertain that the trials are independent and the outcomes are “either the individual saves for retirement or does not save for retirement.”

Therefore, we conclude that the selection of 15 people at random is indeed a binomial experiment.

In question b:

The probability that all selected adults do not save for retirement is mathematically modeled as

P(r = n) = ^nC_r * p^r * q^{n-r}

Here C signifies combination

r = 15 implies all selected adults

n refers to the population size equating to 15

From the problem, p = 0.20

and q can be calculated as

=>

=> q = 1 - p

Thus

P(r = 15) = ^{15}C_{15} * p^{15} * q^{15-15}

P(r = 15) = 3.2768 *10^{-11} Regarding question c:

The probability that exactly five of the selected adults do not save for retirement is mathematically modeled as

P(r = 5) = ^{15} C_5 * (0.20)^5 * (0.80)^{15}

P(r = 5) = 0.1032

In relation to question d:

The probability that at least one of the selected adults opts not to save for retirement can be mathematically expressed as

P(r \ge 1 ) = 1 - P (r = 0 )

P(r \ge 1 ) = 1 - [ ^{15} C _ 0 * (0.20)^{0} * (0.80 )^{15}]

P(r \ge 1 ) = 1 - 0.0352

P(r \ge 1 ) = 0.9648

4 0
2 months ago
Other questions:
  • An electrolyte solution has an average current density of 111 ampere per square decimeter \left( \dfrac{\text{A}}{\text{dm}^2}\r
    6·2 answers
  • If it takes 10 seconds for 10 printers to print out 10 pages of paper, how many seconds will it take 50 printers to print out 50
    14·2 answers
  • The oblique rectangular prism below has a length of 6 cm, a width of 8 cm, and a height of 7 cm.What is the area of the base of
    6·2 answers
  • You buy a pair of jeans at a department store. A receipt, titled "Department Store". It shows the bill for a pair of jeans. Jean
    10·1 answer
  • Four items are purchased at prices of $5.30, $1.29, $.53, and $.68. Sales tax applies at 5% of the total purchase price. What is
    10·2 answers
  • What is the solution to –2|2.2x – 3.3| = –6.6? x = –3 x = 3 x = –3 or x = 0 x = 0 or x = 3
    7·2 answers
  • scholastic books sells 4 times as many textbooks as keller publishing; together they sold 7,775 textbooks. how many did scholast
    10·1 answer
  • What equation do you get when you solve z-m=z+bx for x?
    11·2 answers
  • Complete each statement in the steps to solve x2 – 6x – 7 = 0 using the process of completing the square. Isolate the constant b
    6·2 answers
  • Chuanxi planned a rectangular sidewalk with a length of 21 ft. He made a scale drawing using a scale factor of 1 in. = 7 ft. He
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!