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3 months ago

Draw the three structures of the aldehydes with molecular formula C5H10O that contain a branched chain.

Chemistry

1 answer:

lorasvet [2.7K]3 months ago

7 0

Refer to the image for the answer. An aldehyde is a carbon chain that features a carbonyl group at its end, which is why it is termed aldehyde; if the carbonyl group is elsewhere on the chain, it’s referred to as a ketone. In this case, we have a 5-carbon aldehyde and the first carbon comprises the C=O group, the remaining four making up the chain. However, we must introduce a branched chain into the molecular formula. This means the longest chain cannot maintain a length of 5 carbons; instead, the maximum would be 4 carbons, making the additional carbon the branched unit. We can have two possibilities for the branched chain aldehyde with 5 carbons: one methyl group positioned at 2 and another at 3. Another potential aldehyde with branching cannot exceed 4 carbons as the longest; it must have a 3-carbon chain with 2 carbon radicals (methyl in this context). Thus, the three aldehydes with the specified formula and at least one branch can be represented, alongside their respective names in the attached image.

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Calculate the molarity of 48.0 mL of 6.00 M H2SO4 diluted to 0.250 L

lorasvet [2795]

Answer:

The molality is 1.15 m.

Molality is calculated by dividing the number of moles of solute by the kilograms of solvent, which in this case is water.

Calculate moles of H₂SO₄ from molarity:

C = n/V → n = C × V = 6.00 mol/L × 0.048 L = 0.288 moles

Mass of solvent (water) based on density:

m = ρ × V = 1.00 kg/L × 0.250 L = 0.250 kg

Therefore, molality is:

m = moles/solvent mass = 0.288 moles / 0.250 kg = 1.15 m

4 0

4 months ago

Read 2 more answers

n the table below, write the density of each object. Then predict whether the object will float or sink in each of the fluids. W

Anarel [2989]

Answer:

0.5 g/mL----- will float

1.0 g/mL---- will float

2.0 g/mL----- will sink

Explanation:

Objects with a density less than or equal to that of water will float due to having a lower mass, while objects with a density exceeding that of water will sink because their mass is greater than that of water. Thus, objects with a density of 0.5 g/mL and 1.0 g/mL will float since they are less dense than water (1 g/mL), whereas an object with a density of 2.0 g/mL will sink.

3 0

4 months ago

For no2−, write an equation that shows how the anion acts as a base. express your answer as a chemical equation. identify all of

Anarel [2989]

Hello!

According to Arrhenius, bases are defined as substances that produce OH⁻ ions when they dissolve in water. The anion NO₂⁻ fits this definition as illustrated in the following reaction:

NO₂⁻(aq) + H₂O (l) HNO₂ (aq) + OH⁻(aq)

Wishing you a great day!

5 0

3 months ago

Read 2 more answers

If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4

Anarel [2989]

Answer:

The amount of calcium sulfate that precipitates is 6.14 grams.

Explanation:

Step 1: Provided data

We are mixing 500.0 mL of 0.10 M Ca^2+ with 500.0 mL of 0.10 M SO4^2−

The Ksp for CaSO4 is 2.40×10^−5.

Step 2: Determine moles of Ca^2+

Moles of Ca^2+ = Molarity of Ca^2+ * Volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles of Ca^2+ = 0.05 moles

Step 3: Determine moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

Step 4: Compute total volume

Total volume = 500.0 mL + 500.0 mL = 1000 mL = 1L

Step 5: Compute Q

Q = [Ca2+] [SO42-]

[Ca2+] = 0.050 M and [SO42-]

Qsp = (0.050)(0.050) = 0.0025 >> Ksp

This indicates that precipitation will take place.

Step 6: Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M (molar solubility)

Step 7: Determine total dissolved CaSO4

Total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 g/mol = 0.667 g

Step 8: Calculate initial mass of CaSO4

Initial moles of CaSO4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

Step 9: Calculate precipitate mass

6.807 - 0.667 = 6.14 grams.

The mass of calcium sulfate that will emerge as a precipitate is 6.14 grams.

5 0

3 months ago