<span>(NH4)2CO3 -> 96.09 g/mol
(6.995g ammonium carbonate)(1mol ammonium carbonate/ 96.09 g ammonium carbonate) = 0.072796 mol ammonium carbonate
In this calculation, the unit 'grams' cancels out as it's present in both the numerator and the denominator, leading to 'mol' being the remaining unit.
Examining the formula (NH4)2CO3, it can be interpreted as:
2 mol (NH4) + 1 mol (CO3) = 1 mol (NH4)2CO3
This means every mole of ammonium carbonate yields one mole of carbonate ions and two moles of ammonium ions.
(0.072796 mol ammonium carbonate) = (0.072796 mol carbonate ion) + (0.363981 mol ammonium ion) </span>
The ozonolysis of 2,4,4-trimethyl-2-pentene produces a combination of
and
Explanation: In ozonolysis (where a reducing agent like Zn is involved during hydrolysis), a pi bond cleaves to generate ketones or aldehydes.
Ketones arise from the double bond's disubstituted side, whereas aldehydes come from the monosubstituted side of the same bond.
Notably, ozonolysis comprises two steps: (1) the formation of an ozonide, followed by (2) the hydrolysis of the ozonide.
Hydrolysis can transpire with or without a reducing agent. When it occurs without a reducing agent, carboxylic acid, carbon dioxide, or ketones can be produced.
In this case, 2,4,4-trimethyl-2-pentene yields a mixture of and
The reaction process is illustrated below.
C. The molecule N₂ does not undergo transitions in electronic energy levels due to visible light, whereas transitions occur in I₂ molecules due to visible light.
Explanation:
Molecule absorption of light results in electronic transitions from a ground level to an elevated level matching the energy of the absorbed light.
For nitrogen (N₂), permissible electronic transitions require energy differences corresponding to ultraviolet photon energy. Thus, nitrogen remains colorless as it does not absorb visible light. In contrast, iodine (I₂) facilitates electronic transitions corresponding to visible light photon energies, which gives iodine vapors their violet hue.
Learn more about:
electronic transitions
Answer:
By reducing the height of the center of gravity of the object in relation to its center of buoyancy
Explanation:
In the field of hydrostatics, for a floating object, the state of equilibrium corresponds to either a peak or a trough in potential energy. Stability in equilibrium occurs when the potential energy is minimized. Achieving a lower position of the center of gravity of the floating object compared to its center of buoyancy creates a stable equilibrium arrangement.
