The interest rate equals 25%
Explanation:
Provided data:
Principal amount, P = $2,000
Total amount, A = $2500
Duration, t = 1 year
Interest rate, r =?
We understand:

Substituting the known values gives:


Thus, the interest rate is 25%
Answer:
cuando hables de raviolis de queso, dile a Martha que vaya al supermercado a comprar raviolis Chef Boyardee.
Answer:
The recorded temperature is -0.675ºC.
Detailed explanation:
To tackle problems involving normally distributed samples, the z-score formula can be utilized.
In a distribution with mean
and standard deviation
, the z-score for a specific measure X is calculated as follows:

The Z-score indicates how many standard deviations a given measure deviates from the mean. Once the Z-score is determined, we refer to the z-score table to obtain the corresponding p-value. This p-value represents the likelihood that the measure's value is less than X, thereby indicating the percentile of X. By taking 1 minus the p-value, we find the probability that the measure's value exceeds X.
For this scenario, we know that:
Assuming the thermometer readings follow a normal distribution with a mean of 0◦ and a standard deviation of 1.00◦C, this leads us to 
We need to determine P25, which is the 25th percentile.
This represents the value of X corresponding to Z with a p-value of 0.25, thus we utilize
, applicable between
and
.



The recorded temperature is -0.675ºC.
We can summarize that
By applying the law of cosines:
c² = a² + b² - 2abcos(C)
where:
a,b, and c represent the triangle's sides and C denotes the angle opposing side c.
Let us assign:
a=170 miles
b=200 miles
c=160 miles
Thus, we establish:
160² = 170² + 200² - 2(170)(200)cos(C).
We now aim to solve for C.
25,600 = 28,900 + 40,000 - 68,000cos(C).
25,600 - 28,900 - 40,000 = -68,000cos(C).
-43,300=-68,000cos(C).
Thus, cos(C)=0.6367.
C=arc cos(0.6367)--------> C=50.45°.
Consequently, the captain should adjust toward island B by
180 - 50.45 = 129.55 degrees.
The final answer is
129.55 degrees
.
Utilizing the normal distribution and the central limit theorem, there's a 0.0284 or 2.84% chance of observing a sample mean mass of 695g or less.