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azamat
2 months ago
13

Sodium combines with water to produce sodium hydroxide and hydrogen gas. Which word equation represents this violent reaction?

Chemistry
2 answers:
Tems11 [2.7K]2 months ago
5 0

Response: sodium + water → sodium hydroxide + hydrogen

Clarification: Participating in the quiz right now

.
alisha [2.9K]2 months ago
5 0

Response: sodium + water → sodium hydroxide + hydrogen

Clarification:

1) The initial part of the statement "sodium combines with water" indicates that these pure substances serve as the reactants.

Sodium belongs to the alkali metals (group 1: Li, Na, K, Rb, Cs, Fr).

A common characteristic of alkali metals is their reactive behavior with water, resulting in the formation of the respective hydroxide and hydrogen gas.

2) The following words, "to produce" suggest that what comes next represents the products of the reaction. In chemical equations, this is indicated by the arrow →

3) Finally, it specifies the products of the reaction: sodium hydroxide and hydrogen gas.

4) The word equation observes the sequence reactants → products, translates here as sodium + water → sodium hydroxide + hydrogen

5) Using chemical symbols and formats, this can be represented as:

Na(s) + H₂O (l) → NaOH(aq) + H₂(g).

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What is the kinetic energy acquired by the electron in hydrogen atom, if it absorbs a light radiation of energy 1.08x101 J. (A)
eduard [2782]

Explanation:

The following data has been provided:

Energy of radiation absorbed by the electron in the hydrogen atom = 1.08 \times 10^{-17} J

As energy is absorbed in the form of a photon, the frequency is calculated accordingly:

E = h \nu

1.08 \times 10^{-17} J = 6.626 \times 10^{-34} Js \times \nu

\nu = 0.163 \times 10^{17} s^{-1}

or, \nu = 1.63 \times 10^{16} s^{-1}

It is known that \nu = \frac{c}{\lambda}

1.63 \times 10^{16} s^{-1} = \frac{3 \times 10^{8} m/s}{\lambda}

\lambda = 1.84 \times 10^{-8} m

According to the De-Broglie equation \lambda = \frac{h}{p}

with p = m \times \nu

So, \lambda = \frac{h}{m \times \nu}

m \times \nu = \frac{6.626 \times 10^{-34} Js}{1.84 \times 10^{-8} m} = 3.6 \times 10^{-26} J/m

Squaring both sides gives us:

(m \times \nu)^{2} = (3.6 \times 10^{-26} J/m)^{2}

12.96 \times 10^{-52} = m \times \nu^{2} = \frac{12.96 \times 10^{-52}}{m}

where m = mass of the electron

Therefore, m \times \nu^{2} = \frac{12.96 \times 10^{-52}}{m}

=\frac{12.96 \times 10^{-52}}{9.1 \times 10^{-31}}

=1.42 \times 10^{-21} J

Since K.E = \frac{1}{2}m \nu^{2}

= \frac{1.42 \times 10^{-21} J}{2}

=0.71 \times 10^{-21} J

Our conclusion is that the kinetic energy gained by the electron in the hydrogen atom is 7.1 \times 10^{-22} J.

4 0
2 months ago
What features of this model will help Armando answer the question?
lions [2927]

Answer:

The adjustable legs along with the sand table.

Note: The question is incomplete. The full question is presented below.

Using Models to Address Questions Regarding Systems

Armando’s class was examining images of rivers shaped by flowing water. Most rivers appeared wide and shallow, except for one, which was narrow and deep. The students theorized that this river's narrowness and depth are due to:

  • the steepness of the hill from which the water descends, or
  • the diminutive size of the sand grains the water flows through.

To explore the answer to the question of why this river is so narrow and deep, Armando created the model outlined below.

Explanation:

The model constructed by Armando will facilitate addressing the question due to specific features:

1. Adjustable leg - as one theory proposed by the class suggests that the steep hill affecting the water's path could be the reason for the river's dimensions, the adjustable legs are designed to be raised or lowered to alter the slope, allowing testing of this theory.

2. Sand table - this acts as the streambed. By modifying the size of the sand grains, students can examine the second hypothesis that smaller sand grains contribute to the river's narrowness and depth.

The outcomes of their experimentation will lead them to a conclusion.

5 0
2 months ago
Read 2 more answers
If 3.8 kcal is released by combustion of each gram of glucose, how many kilocalories are released by the combustion of 1.50 mol
castortr0y [3046]
684 kcal. One mole of glucose weighs roughly 180g. Given that 1g of glucose releases 3.8 kcal, we calculate for 1 mole of glucose: 180g -> 180g * 3.8 kcal/g = 684 kcal.
7 0
2 months ago
A particular car has a gas mileage of 24.5 miles per gallon. If the cost of gas is $4.25 per gallon, and the car travels at a co
KiRa [2933]

Response:

$30.39

Rationale:

a lot of calculations

3 0
1 month ago
Which of the following is transferred due to a temperature difference?
lions [2927]
Water transitions to ice when temperatures drop too low, while it turns into gas when temperatures rise too high.
Conversely, ice transforms back into water when heated, remaining unchanged if temperatures are too low.
Furthermore, gas transitions to water when cooled and can freeze into ice if cooled further, continuing this cycle.
I hope this clarifies things.
 
8 0
1 month ago
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