Moving on to the second issue
Let's tackle the second question first. Once you grasp that, the first question will be simpler. By the way, this is an excellent question to clarify. The concepts of less than and more than can be quite tricky in the sciences. Every question you encounter that utilizes less or more should be approached with caution.
As altitude increases, air pressure decreases (essential term: less highlight this sentence in color. Take a moment to reflect on it.)
As the pressure declines, less energy (again, key term) is required for water molecules to escape the surface. Thus, the boiling temperature is lower than it would be at sea level.
Answer to problem two: Lower
Problem One
Water reaches its boiling point when the greatest number of molecules can leave the water's surface. Equal to is the right answer. Although pinpointing the exact answer can be challenging, equal to is indeed the correct response.
Response:
The specific heat of the alloy 
Clarification:
Weight of the alloy 
= 25 gm
Initial temperature 
= 100°c = 373 K
Weight of the water 
= 90 gm
Initial temperature of water 
= 25.32 °c = 298.32 K
Final temperature 
= 27.18 °c = 300.18 K
Using the energy balance equation,
Heat released by the alloy = Heat absorbed by the water
[[ - ] = 
( - )
25 × × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)
This gives us the specific heat of the alloy.
Answer:
vHe / vNe = 2.24
Explanation:
To determine the velocity of an ideal gas, one should apply the formula:
v = √3RT / √M
In this equation, R represents the gas constant (8.314 kgm²/s²molK); T refers to temperature, and M indicates the molar mass of the gas (4x10⁻³kg/mol for helium and 20.18x10⁻³ kg/mol for neon). Hence:
vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol
vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol
The ratio simplifies to:
vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol
vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol
vHe / vNe = 2.24
I hope it assists you!
