What is the maximum number of hydrogen atoms that can be covalently bonded in a molecule containing two carbon atoms?a) 2b) 3c)
4d) 6e) 8?
1 answer:
Response:
The right answer is Option-D (6 Hydrogen atoms).
Clarification:
Carbon possesses a special characteristic that allows it to bond with itself, forming a chain known as Catenation. In a molecule with two carbon atoms, there has to be a bond between them. This bond can either be saturated (simple single bond) or unsaturated (double or triple bond). Since the question mentions the maximal number of hydrogen atoms, we will assume the bond between the two carbon atoms to be single.
Each carbon has four valence electrons, enabling them to form four single bonds. In this molecule, every carbon atom has already bonded with another carbon atom through a single bond, leaving each carbon with three unpaired electrons that will form covalent bonds with three hydrogen atoms each, as illustrated in the attached diagram.
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Answer:
Explanation:
Greetings,
According to the provided chemical equation, the production of 31.2 mL of hydrogen allows one to calculate its moles using the ideal gas equation as detailed below:
Since the ratio of hydrogen to magnesium is 1:1, its milligrams are derived through the following proportional factor calculation:
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Answer:- 0.134 seconds
Solution:- The speed is given as and the circumference is 24900 miles which is same as the distance light have to covered. It asks to calculate the time required to cover this distance by the light.
Unit conversion is needed from miles to meters since the speed is given in meters per second.
1 mile = 1609.34 meters
Thus,
= 40072566 meters
Now,
Rearranged for time, that gives:
Inserting the values:
= 0.134 seconds
Hence, light would take 0.134 seconds to traverse the indicated distance. The answer without the unit is 0.134.
Answer: The percentage abundance for isotope is 3.09 %.
Explanation:
The average atomic mass of an element is calculated by taking the sum of the masses of all isotopes weighted by their respective natural fractional abundances.
To compute average atomic mass, the following formula is applied:
.....(1)
From the information provided:
Let the fractional abundance for isotope be 'x'
- For
isotope:
Mass of isotope = 27.9769 amu
Percentage abundance of isotope = 92.22 %
Fractional abundance for isotope = 0.9222
- For
isotope:
Mass of isotope = 28.9764 amu
Percentage abundance for isotope = 4.68%
Fractional abundance of isotope = 0.0468
- For
isotope:
Mass of isotope = 29.9737 amu
Fractional abundance for isotope = x
- The average atomic mass of silicon is 28.084 amu
By inserting these values into equation 1, we derive:
To convert this fractional abundance into a percentage, multiply by 100:
This shows that the percentage abundance for isotope is 3.09 %.