Although multiple values are given, our focus is on HCl.
<span>We have 215 mL (0.215 L) of 0.300 M HCl fully consumed in the reaction. It's important to recall that the number of moles is found by multiplying volume by molarity:</span>
moles = 0.215 L × 0.300 M
<span>moles = 0.0645 moles of HCl</span>
Response:
0.8853 mL
Clarification:
Initially, we convert 13 lb to kg, remembering that 1 lb = 0.454 kg:
- 13 lb *
= 5.902 kg
Next, we determine the required mg of acetaminophen to administer, applying the recommended dosage and infant's weight:
- 15 mg/kg * 5.902 kg = 88.53 mg
Finally, we compute the necessary mL of suspension, utilizing its concentration:
- 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL
Consequently, she feels very anxious because she has 345600 seconds to wait. Explanation: 60 seconds make up 1 minute, and 60 minutes constitute an hour. Each hour has 3600 seconds (60*60) and 24 hours make up a day. Hence, 3600 seconds multiplied by 24 hours results in 1 day equating to 86400 seconds—therefore, over four days, we have 86400 * 4 equating to 345600.
The visual representation is displayed in the following image.
For calculations, consider 100 grams of the compound:
ω(Cl) = 85.5% ÷ 100%.
ω(Cl) = 0.855; signifying the mass percentage of chlorine in the compound.
m(Cl) = 0.855 · 100 g.
m(Cl) = 85.5 g; this represents the mass of chlorine.
m(C) = 100 g - 85.5 g.
m(C) = 14.5 g; indicating the mass of carbon.
n(Cl) = m(Cl) ÷ M(Cl).
n(Cl) = 85.5 g ÷ 35.45 g/mol.
n(Cl) = 2.41 mol; this is the quantity of chlorine.
n(C) = 14.5 g ÷ 12 g/mol.
n(C) = 1.21 mol; this is the quantity of carbon.
n(Cl): n(C) = 2.41 mol: 1.21 mol = 2: 1.
The compound in question is identified as dichlorocarbene CCl₂.
The change in temperature can be expressed as:

By substituting in the known values, we arrive at:

Thus, we obtain the required answer.