What percentage of solar radiation striking a plant is converted into chemical energy?

Response:water

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To tackle this problem, one must first determine the specific heat of water, which is the energy required to raise the temperature of 1 g of water by 1 degree C. The relationship is given by the formula q = c X m X delta T, where q indicates the specific heat of water, m signifies the mass, and delta T denotes the temperature change. The specific heat of water is 4.184 J/(g X degree C). The temperature of the water increased by 20 degrees, therefore: 4.184 x 713 x 20.0 = 59700 J, rounded to 3 significant digits, equals 59.7 kJ. This value indicates the energy required to produce B2O3 from 1 gram of boron. To convert this to kJ/mole, additional calculations are required. The gram atomic mass of Boron is 10.811, so dividing 1 gram of boron by 10.811 results in.0925 moles of boron. Given that 2 moles of boron are needed for the formation of 1 mole of B2O3, dividing the moles of boron by two yields.0925/2 =.0462 moles. Consequently, dividing the energy in KJ by the number of moles provides KJ/mole: 59.7/.0462 = 1290 KJ/mole.

The connection between Gibb's free energy and temperature can be described as follows. The value for is specified as 1.7 kJ/mol. Additionally, we know that k =

= . Since k has a value of 0.50357 at a temperature of 298 K, we can conclude that

= 0.50357, leading to + 1 = 1.50357, which equals = 0.665. Therefore, we can deduce that 0.665 of the total fructose in the solution exists as fructopyranose.