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AlekseyPX
3 months ago
9

An object moving at a constant velocity travels 274 m in 23 s. what is its velocity?

Physics
2 answers:
Softa [3K]3 months ago
6 0
V= 274 meters / 23 sec

V= 11.91 meters per sec
ValentinkaMS [3.4K]3 months ago
4 0

Solution:

Velocity, v = 11.91 m/s

Justification:

We have the following details:

Distance traveled by the object, d = 274 m

Time taken, t = 23 s

We are tasked with determining the object's velocity. It can be calculated using the formula of distance divided by time, that is,[[(TAG_19]]

v=\dfrac{d}{t}

v=\dfrac{274\ m}{23\ s}

v = 11.91 m/s

Thus, the object's velocity is 11.91 m/s. This is the solution we seek.

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If points a and b are connected by a wire with negligible resistance, find the magnitude of the current in the 12.0 v battery.
ValentinkaMS [3465]
V = I * R, where V signifies voltage, I represents current, and R is resistance. According to Ohm's law, to determine the current through the wire, resistance is required. In theory, if the wire had zero resistance, it would lead to infinite current, which is not feasible. This negligible resistance could refer to the internal resistance of the battery rather than the wire itself. 
7 0
2 months ago
It's a snowy day and you're pulling a friend along a level road on a sled. You've both been taking physics, so she asks what you
Maru [3345]

Answer:

0.0984

Explanation:

The first diagram below illustrates a free body diagram that will aid in resolving this problem.

According to the diagram, the force's horizontal component can be expressed as:

F_X = F_{cos \ \theta}

Substituting 42° for θ and 87.0° for F

F_X =87.0 \ N \ *cos \ 42 ^\circ

F_X =64.65 \ N

Meanwhile, the vertical component is:

F_Y = Fsin \ \theta

Again substituting 42° for θ and 87.0° for F

F_Y =87.0 \ N \ *sin \ 42 ^\circ

F_Y =58.21 \ N

In resolving the vector, let A denote the components in mutually perpendicular directions.

The magnitudes of both components are illustrated in the second diagram provided and can be represented as A cos θ and A sin θ

The frictional force can be expressed as:

f = \mu \ N

Where;

\mu is the coefficient of friction

N = the normal force

Also, the normal reaction (N) is calculated as mg - F sin θ

Substituting F_Y \ for \ F_{sin \ \theta}. Normal reaction becomes:

N = mg \ - \ F_Y

By balancing the forces, the horizontal component of the force equals the frictional force.

The horizontal component is described as follows:

F_X = \mu \ ( mg - \ F_Y)

Rearranging the equation above to isolate \mu leads to:

\mu \ = \ \frac{F_X}{mg - F_Y}

Substituting in the following values:

F_X \ = \ 64.65 \ N

m = 73 kg

g = 9.8 m/s²

F_Y = \ 58.21 N

Thus:

\mu \ = \ \frac{64.65 N}{(73.0 kg)(9.8m/s^2) - (58.21 \ N)}

\mu = 0.0984

Therefore, the coefficient of friction is = 0.0984

5 0
3 months ago
A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i
Sav [3153]

Respuesta:

11.4 m/s

Explicación:

La fórmula para la aceleración centrípeta es:

a=\frac{v^2}{R}

donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.

En este problema,

a = g = aceleración debida a la gravedad en la cima = 9.81\ m/s^2

v = ?

R = 13.2 m

Por lo tanto,

9.81=\frac{v^2}{13.2}

v^2=9.81\times {13.2}

v = 11.4 m/s

8 0
4 months ago
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