Answer:
Clarification:
Based on the given
the skateboarder's speed is 4.1 m/s
Force
time=20 s
Since the movement is along the x direction, we will consider only the x component of force since there is no movement in the y direction.
The work done equals
The work done on the skateboarder by the rope is 1148 J
Answer:
The mass will be 4.437 kg
Explanation:
The force constant k is given as 7 N/m
The time period of oscillation T is 5 sec
Thus, angular frequency
It is known that angular frequency is computed via
Squaring both sides gives us
The mass equals 4.437 kg
Response:
U = 12,205.5 J
Clarification:
To determine the internal energy of an ideal gas, use the following equation:
(1)
U: internal energy
R: ideal gas constant = 8.135 J(mol.K)
n: number of moles = 10 mol
T: the temperature of the gas = 100K
Substituting the parameter values into equation (1):
The overall internal energy for 10 moles of Oxygen at 100K is 12,205.5 J
Answer:
x = v₀ cos θ t, y = y₀ + v₀ sin θ t - ½ g t2
Explanation:
This pertains to a projectile motion scenario. Here, we will express the equations for both the x and y dimensions.
Now, we will apply trigonometry to determine the initial velocity components.
sin θ = / v₀
cos θ = v₀ₓ / v₀
v_{y} = v_{oy} sin θ
v₀ₓ = v₀ cos θ
Next, let's formulate the equations of motion.
X axis
x = v₀ₓ t
x = v₀ cos θ t
vₓ = v₀ cos θ
Y axis
y = y₀ + t - ½ g t2
y = y₀ + v₀ sin θ t - ½ g t2
v_{y} = v₀ - g t
v_{y} = v₀ sin θ - gt
= v_{oy}^2 sin² θ - 2 g y
It is evident that the major distinction lies in the fact that in an inclined launch compared to a horizontal one, the velocity comprises different components
Explanation:
We are given that,
Mass of the rocket,
(a) The standard unit of mass is kilogram (kg). The conversion between slugs and kilograms is as follows:
1 slug = 14.59 kg
Thus,
Mass of the rocket, m = 3647500 kg
(b) The weight of the rocket can be expressed as:
W = m g
or
(c) If the rocket were on the moon, the gravitational acceleration on the moon is given as
Mass refers to the quantity of matter present in an object. Therefore, the mass of the rocket remains constant at 3647500 kg
The weight of the rocket on the moon would be,
W = 5872475 N
or
Thus, this is the final answer required.