A block of foam has a mass of 10 g, a volume of 60 cm3, and a length of 30 cm. What is the density of the foam? (If necessary, r

Answer:

a. Angle= 28.82°

b. Approved. Although he might feel cold, he should be able to cross.

Explanation:

Velocity Vector

Velocity is a measure of how quickly something is moving in a specific direction. It is represented as a vector that has both magnitude and direction. If an object can only move in one direction, then speed can serve as the scalar equivalent of that velocity (only focusing on magnitude).

a.

The explorer aims to swim across a river to reach his campsite, as depicted in the image below. The river's velocity is vr and the explorer's swimming speed in still water is ve. If he were to swim straight towards the campsite, he would end up downstream due to the river's current. Therefore, he must swim at an angle that allows him to overcome the current while still moving towards his goal. This angle relative to the shore is what we need to determine. The explorer's speed can be broken down into its horizontal (vx) and vertical (vy) components. In order to counteract the river's flow:

We can calculate the vertical component of the explorer's swimming speed as

Thus

Finding the value of

Then the angle is given by

b.

The component of the explorer's velocity that goes horizontally is

This represents the actual velocity directed towards the campsite

Considering that

To find t

Calculating the duration for the explorer to cross the river

As this time is under the hypothermia threshold (300 seconds), the conclusion is

Approved. Although he will feel cold, he should manage to cross successfully.

Let Cp represent the specific heat of the metal object. To find this, we can set up a heat balance equation (heat lost by metal = heat gained by water):

- 19g * Cp * (22degC – 96degC) = 75g * 4.184J/g degC * (22degC - 18degC)

<span>Cp = 0.893 J/g degC</span>

Answer:

The density comes out to be Mg/µL

Explanation:

Given data:

The density of nuclear matter is approximately kg/m³

1 ml corresponds to 1 cm³

To determine:

The density of nuclear matter in Mg/µL

Solution:

We recognize that:

1 Mg equals 1000 kg

Thus, 1 m³ is equal to cm³

Moreover, 1 cm³ is equivalent to 1 mL

Thus, we can conclude that 1 mL is equal to 10³ µL

With this, we convert the density as follows:

Density = kg/m³

Density = kg/m³ ×  Mg/µL

Density = Mg/µL

Answer:

As indicated in the attached document

Explanation:

The comprehensive steps, mathematical reasoning, and manipulations are presented in the attachment.

Answer:

Please refer to the explanation

Explanation:

Race distance is 5km

Top speed = 45 yards

Converting yards to kilometers:

1km equals 1093.613 yards

x = 45 yards

(1093.613 * x) = 45

x = 45 / 1093.613

x = 0.0411480 km

Where x indicates the maximum distance he can sustain his highest speed in kilometers.

Thus, from the data available, we can determine that Lamar will not be able to maintain his maximum speed for the full 5km race, as he can only sustain it for 0.0411 kilometers.