How, if at all, would the equations written in Parts C and E change if the projectile was thrown from the cliff at an angle abov
1 answer:
Answer:
x = v₀ cos θ t, y = y₀ + v₀ sin θ t - ½ g t2
Explanation:
This pertains to a projectile motion scenario. Here, we will express the equations for both the x and y dimensions.
Now, we will apply trigonometry to determine the initial velocity components.
sin θ = / v₀
cos θ = v₀ₓ / v₀
v_{y} = v_{oy} sin θ
v₀ₓ = v₀ cos θ
Next, let's formulate the equations of motion.
X axis
x = v₀ₓ t
x = v₀ cos θ t
vₓ = v₀ cos θ
Y axis
y = y₀ + t - ½ g t2
y = y₀ + v₀ sin θ t - ½ g t2
v_{y} = v₀ - g t
v_{y} = v₀ sin θ - gt
= v_{oy}^2 sin² θ - 2 g y
It is evident that the major distinction lies in the fact that in an inclined launch compared to a horizontal one, the velocity comprises different components
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Explanation:
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