Response: 1000
Rationale: because 5 cubic meters equals 5000 liters
False, it's solely heterogeneous. Explanation: The degradation of the ozone layer caused by CFC molecules happens in the gaseous state since it does not involve liquids or solids at stratospheric conditions. Additionally, the reaction occurs independently as ozone is chemically unstable, eliminating the need for a catalyst.
Response: The moles in 369 grams of calcium hydroxide are 4.98 moles
Reasoning: Given,
Mass of calcium hydroxide = 369 g
Molar mass of calcium hydroxide = 74.093 g/mole
Formula used:

Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.

Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles
The inquiry is incomplete; here is the full question:
One tank of goldfish receives the standard amount of feeding once daily, a second tank is given two feedings a day, and a third tank is fed four times daily throughout a six-week experiment. The body fat of the fish is recorded every day.
Independent Variable-
Dependent Variable-
Constants
Control Group-
Answer:
A) The quantity of food given to the goldfish
B) The body fat of the goldfish
C) -Type of fish in the experiment (goldfish)
Time period for feeding the fish (six weeks)
Shape and size of the tanks
D) group of goldfish receiving the standard feeding amount
Explanation:
The objective of the experiment is to assess how the quantity of food affects the body fat of goldfish. Consequently, the amount of food serves as the independent variable while the body fat acts as the dependent variable.
The control group is the one given the standard feeding amount (once daily). All subjects are goldfish, fed over a six-week duration, with all tanks being the same shape and size, establishing the constants in the research.
Answer:
0.31%
Explanation:
For the chemical reaction:
I₂ + 2 S₂O₃²⁻ → 2 I⁻ + S₄O₆²⁻
0.043 L multiplied by 0.117 M of sodium thiosulfate gives 5.031x10⁻³ moles of S₂O₃²⁻
5.031x10⁻³ moles of S₂O₃²⁻ produces:
ClO⁻⁻ + 2 H⁺ + 2 I⁻ → I₂ + Cl⁻ + H2O
2.5156x10⁻³ moles of I₂ equates to moles of NaClO
2.5156x10⁻³ moles of NaClO times
yields 0.187 g of NaClO
Thus, the mass percentage composition is:
= 0.31%
I hope this helps!