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monitta
1 month ago
14

Convert 338 L at 63.0 atm to its new volume at standard pressure.

Chemistry
1 answer:
lions [2.9K]1 month ago
7 0

The new volume at a standard pressure of 1 atm is 21294 liters.

Explanation:

Provided data:

Initial volume of the gas V1 = 338 liters

Initial pressure on the gas P1 = 63 atm

Standard pressure P2 = 1 atm

Final volume at standard pressure V2 =?

The equation of Boyle's law is applied here:

P1V1 = P2V2

To find V2, rearranging gives us:

V2 = \frac{P1V1}{P2}

Substituting the values:

V2 = \frac{338X63}{1}

     = 21294 L

When the pressure is lowered to 1 atm, the gas volume expands significantly to 21294 liters.

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In my opinion,
when two distinct forces are exerted in opposite directions, the resultant force is the subtraction of those forces
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a movable chamber has a volume of 18.5 L (at temperature of 18.5 C) assuming no gas escapes and the pressure remains constant wh
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Answer:

39 ^\circ C

Explanation:

We have:

V₁ = 18.5 L

T₁ = 18.5° C = 273 + 18.5 = 291.5 K

V₂ = 19.8 L

T₂ =?

Pressure remains constant

Applying the ideal gas law

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

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1 month ago
A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
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Explanation:

Horizontal distance separating the two molecules is 16.5 nm.

Width of the 10^5 molecules:16.5 nm\times 10^5=16.5\times 10^5 nm

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The overall width of a crystal measured in millimeters=16.5\times 10^5\times 10^{-6} mm=1.65 mm

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1 month ago
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You have a racemic mixture of d-2-butanol and l-2-butanol. the d isomer rotates polarized light by +13.5∘. what is the rotation
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1 month ago
The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr
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Response:

The pKa value is 13.0.

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For trimethylamine, Kb = 6.3 × 10^{-5}

Calculating pKb: pKb = - log (6.3 × 10^{-5})

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